我有一个字符串，如下
<img alt="rlogo" src="https://something.net/logo.gif/resized_logo.png?r=3" />
<p>
<strong>Headquarters:</strong> Austin, TX
<br /><strong>URL:</strong> <a href="https://something.com/F402B805CC">https://something.com/j/F402B805CC</a>
</p>
Lorem ipsum dollar sit amet
我想删除除"Lorem ipsum美元坐amet"以外的所有内容，到目前为止，我设法使用删除了图像标签
preg_replace('<img alt='"rlogo'".*>','',$description)
但这对<p>标签不起作用，因为<p>标签后面有新行。
有什么方法可以删除从<img到</a></p>的所有
使用s选项（点匹配换行符）；
$result = preg_replace('%<img.*?</p>%si', '', $description);
Regex Explanation
<img.*?</p>
Options: Case insensitive (i); Exact spacing; Dot matches line breaks (s); ^$ don’t match at line breaks; Greedy quantifiers; Regex syntax only
Match the character string “<img” literally (case insensitive) «<img»
Match any single character «.*?»
Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the character string “</p>” literally (case insensitive) «</p>»