我有一个提交表单，其中有一个名为case_no的字段，当我输入case_no时，它应该用与case_no匹配的特定信息填充表。
控制器：
public function actionSearch()
{
$model = new LegalCase();
$category = new Category();
/*$categories = Category::findAll();*/
if ($model->load(Yii::$app->request->post())) {
Yii::$app->session->setFlash('searchFormSubmitted');
$case = $model->findByCaseNo($case_no);
return $this->render('search', [
'model' => $model,
'dataProvider' => $model->findAll(),
'results' => $case
]);
return $this->refresh();
} else {
return $this->render('search', [
'model' => $model,
]);
}
}
型号：
class LegalCase extends Model
{
public $id;
public $case_no;
public $name;
public $judgement_date;
public $year;
public $neutral_citation;
private static $cases = [
'100' => [
'id' => '1',
'case_no' => '3',
'name' => 'first case'
],
'101' => [
'id' => '1',
'case_no' => '125',
'name' => 'second case'
],
];
/**
* @inheritdoc
*/
public static function findAll()
{
//$query = new Query();
$provider = new ArrayDataProvider([
'allModels' => self::$cases,
'sort' => [
'attributes' => ['id', 'case_no', 'name'],
],
'pagination' => [
'pageSize' => 10,
],
]);
return $provider->getModels();
}
/**
* @inheritdoc
*/
public static function findIdentity($id)
{
return isset(self::$cases[$id]) ? new static(self::$cases[$id]) : null;
}
/**
* Finds case by name
*
* @param string $name
* @return static|null
*/
/**
* Finds case by number
*
* @param string $case_no
* @return static|null
*/
public static function findByCaseNo($case_no)
{
foreach (self::$cases as $case) {
if (strcasecmp($case['case_no'], $case_no) === 0) {
return new static($case);
}
}
return null;
}
视图：
<?php
use yii'helpers'ArrayHelper;
use yii'helpers'Html;
use yii'bootstrap'ActiveForm;
use yii'widgets'ListView;
use app'models'LegalCase;
use backend'models'Standard;
/* @var $this yii'web'View */
/* @var $form yii'bootstrap'ActiveForm */
/* @var $model app'models'LegalCase */
$this->title = 'Search';
$this->params['breadcrumbs'][] = $this->title;
?>
<div class="site-login">
<h1><?= Html::encode($this->title) ?></h1>
<p>Please fill out the following fields to login:</p>
<?php $form = ActiveForm::begin([
'id' => 'search-form',
'options' => ['class' => 'form-horizontal'],
'fieldConfig' => [
'template' => "{label}'n<div class='"col-lg-3'">{input} </div>'n<div class='"col-lg-8'">{error}</div>",
'labelOptions' => ['class' => 'col-lg-1 control-label'],
],
]); ?>
<?= $form->field($model, 'case_no') ?>
<?= $form->field($model, 'name') ?>
<?php /*= Html::activeDropDownList($model, 's_id',
ArrayHelper::map(Standard::find()->all(), 's_id', 'name'))*/ ?>
<?php
?>
<div class="form-group">
<div class="col-lg-offset-1 col-lg-11">
<?= Html::submitButton('Search', ['class' => 'btn btn-primary', 'name' => 'search-button']) ?>
</div>
</div>
<?php if (Yii::$app->session->hasFlash('searchFormSubmitted')) { ?>
<table class="table table-striped">
<tr>
<th>ID</th>
<th>case_no</th>
<th>name</th>
</tr>
</table>
<?php //$posts = $results->getModels();
foreach($results as $case){
echo '<tr>';
//print_r($case);
echo $case;
//echo $case->id;
/*echo '<td>' . $post['id'] . '</td>';
echo '<td>' . $post['case_no'] . '</td>';
echo '<td>' . $post['name'] . '</td>';*/
echo '</tr>';
} ?>
知道为什么不起作用吗？
使用$_POST['LegalCase']['case_no']而不是$case_no。
编辑：注意：我使用的是旧版本的Yii，所以情况可能已经改变了。
您需要这样做：
$case = $model->findByCaseNo($model->case_no);
但是表单提交后，您的属性$case_no将为空。发生这种情况是因为属性不安全。函数load（）仅设置安全模型属性。如果您想在提交后加载模型属性，则需要向LegalBase模型添加验证。例如：
public function rules()
{
return [
['case_no', 'trim'],
];
}