PHP和MYSQLI在几个月内循环 - PHP and MYSQLI looping through months

PHP and MYSQLI looping through months

本文关键字：循环几个月 MYSQLI PHP | 更新日期: 2023-09-27

我试图检索每个月的数据（01、02、03等），但我不知道如何循环。现在我每个月都有这个！（如果你跳过了其他几个月，这样你就不必看到所有的）。

 $queryJanuary = "SELECT count(*) AS num FROM unique_ip WHERE datum BETWEEN '2016-01-01' AND '2016-01-31'";
 $queryFebruari = "SELECT count(*) AS num FROM unique_ip WHERE datum BETWEEN '2016-02-01' AND '2016-02-28'";

     if ($January = $Connection->query($queryJanuary)) {
          $Februari  = $Connection->query($queryFebruari);
            $rowJanuari = mysqli_fetch_assoc($January);
            $rowFebruari  = mysqli_fetch_assoc($Februari);
            $january   = $rowJanuari['num'];
            $februari  = $rowFebruari['num'];
     }else {
         die();
           }
      $data = array($january, $februari);
     echo json_encode($data);

数据库方案：

IP无符号INT-PK
基准日期不为空
告知INT NOT NULL-默认1
- 基准指日期
- 数数

此外，将查询转换为准备好的语句是方便的还是至少是好的做法？此代码只能在只有我和其他管理员才能访问的私人页面上使用。

尝试以下查询。这将帮助您在单个查询中获取所有月份的计数。

$queryallmonth = "SELECT MONTHNAME(datum) Month,COUNT(ip) num FROM unique_ip GROUP BY DATE_FORMAT(datum, '%Y%m')"

使用查询：

SELECT count(*) AS num, EXTRACT(YEAR_MONTH FROM datum) as yearmonth  FROM unique_ip WHERE datum BETWEEN '2016-01-01' AND '2016-05-02' GROUP BY EXTRACT(YEAR_MONTH FROM datum) DESC";

此SQL将为您提供按月计数。。

我真的不知道你打算做什么，但试一下你的SQL:

$queryJanuary    = "SELECT count(datum) AS num FROM unique_ip WHERE (datum>='2016-01-01' AND datum<='2016-01-31')";
$queryFebruari   = "SELECT count(datum) AS num FROM unique_ip WHERE (datum>='2016-02-01' AND datum<='2016-02-28')";
$data            = array(); //INITIALIZE DATA TO AN EMPTY ARRAY...
try{
    $January     = $Connection->query($queryJanuary);
    $Februari    = $Connection->query($queryFebruari);
    $rowJanuari  = mysqli_fetch_assoc($January);
    $rowFebruari = mysqli_fetch_assoc($Februari);
    $january     = $rowJanuari['num'];
    $februari    = $rowFebruari['num'];
    $data        = array($january, $februari);
}catch(Exception $e){
    //HANDLE YOUR EXCEPTION HERE...
    die();
}
echo json_encode($data);

您还可以在一个SQL语句中完成所有这些操作，如下所示：

$queryAll       = "SELECT COUNT(datum) AS countJan,
                   (SELECT COUNT(datum) FROM unique_ip WHERE (datum>='2016-02-01' AND datum<='2016-02-28')) AS countFeb  
                   FROM unique_ip AS af WHERE (datum>='2016-01-01' AND datum<='2016-01-31')";
$data            = array(); //INITIALIZE $data TO AN EMPTY ARRAY...
$rowAll          = array(); //INITIALIZE $rowAll TO AN EMPTY ARRAY...
try{
    $query       = $Connection->query($queryAll);
    $rowAll      = mysqli_fetch_assoc($query);
    $january     = $rowAll['countJan'];
    $februari    = $rowAll['countFeb'];
    $data        = array($january, $februari);
    // BUT YOU DON NOT NEED TO PUSH $january & $februari INTO THE $data ARRAY 
    // BECAUSE YOU HAVE THOSE VALUES ALREADY INSIDE THE $rowAll VARIABLE 
    // WHICH SHOULD CONTAIN THESE KEYS: "countJan" & "countFeb"
}catch(Exception $e){
    //HANDLE YOUR EXCEPTION HERE...
    die();
}
//DUMP THE VALUES TO SEE IF THEY ARE WHAT YOU EXPECTED 
var_dump($data);
var_dump(rowAll);