我使用以下指南使用谷歌地图创建商店定位器：https://developers.google.com/maps/articles/phpsqlsearch_v3
到目前为止，我没有收到任何错误，但我无法将数据库中的数据显示为XML。相反，它显示以下内容：
This XML file does not appear to have any style information associated with it. The document tree is shown below.
<locations/>
它只显示了文档的末尾，但没有返回任何数据。
这是我迄今为止的代码：
<?php
require("dbinfo.php");
// Get parameters from URL
$center_lat = $_GET["lat"];
$center_lng = $_GET["lng"];
$radius = $_GET["radius"];
// Start XML file, create parent node
$dom = new DOMDocument("1.0");
$node = $dom->createElement("locations");
$parnode = $dom->appendChild($node);
// Opens a connection to a mySQL server
$connection=mysql_connect ($hostname, $username, $password);
if (!$connection) {
die("Not connected : " . mysql_error());
}
// Set the active mySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
die ("Can''t use db : " . mysql_error());
}
// Search the rows in the locations table
$query = sprintf("SELECT address, name, lat, lng, ( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) ) AS distance FROM locations HAVING distance < '%s' ORDER BY distance LIMIT 0 , 20",
mysql_real_escape_string($center_lat),
mysql_real_escape_string($center_lng),
mysql_real_escape_string($center_lat),
mysql_real_escape_string($radius));
$result = mysql_query($query);
$result = mysql_query($query);
if (!$result) {
die("Invalid query: " . mysql_error());
}
header("Content-type: text/xml");
// Iterate through the rows, adding XML nodes for each
while ($row = @mysql_fetch_assoc($result)){
$node = $dom->createElement("locations");
$newnode = $parnode->appendChild($node);
$newnode->setAttribute("name", $row['name']);
$newnode->setAttribute("address", $row['address']);
$newnode->setAttribute("lat", $row['lat']);
$newnode->setAttribute("lng", $row['lng']);
$newnode->setAttribute("distance", $row['distance']);
}
echo $dom->saveXML();
?>
我的表名是"locations"。
我以前遇到过sql错误，但通过纠正之前犯下的数据库连接错误，我成功地将其传递给了数据库，因此我确信它已连接到数据库。
如有任何帮助或建议，我们将不胜感激。
感谢
Mike
您的代码还可以。主要问题是google在这个链接中提供了https://developers.google.com/maps/articles/phpsqlsearch_v3不包含25半径内地址的样本位置。因此，您需要在URL 中将半径从25更改为28或30
phpsqlsearch_genxml.php?lat=37&lng=-122&radius=28
尽管你的代码中可能有一些错误。所以我在这里提供我的代码。
<?php
require("phpsqlsearch_dbinfo.php");
// Get parameters from URL
$center_lat = $_GET["lat"];
$center_lng = $_GET["lng"];
$radius = $_GET["radius"];
// Start XML file, create parent node
$dom = new DOMDocument("1.0");
$node = $dom->createElement("markers");
$parnode = $dom->appendChild($node);
// Search the rows in the markers table
$query = sprintf("SELECT address, name, lat, lng, ( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) ) AS distance FROM markers HAVING distance < '%s' ORDER BY distance LIMIT 0 , 20",
mysqli_real_escape_string($connection,$center_lat),
mysqli_real_escape_string($connection,$center_lng),
mysqli_real_escape_string($connection,$center_lat),
mysqli_real_escape_string($connection,$radius));
$result = mysqli_query($connection,$query);
if (!$result) {
die("Invalid query: " . mysqli_error($connection));
}
header("Content-type: text/xml");
// Iterate through the rows, adding XML nodes for each
while ($row = @mysqli_fetch_assoc($result)){
$node = $dom->createElement("marker");
$newnode = $parnode->appendChild($node);
$newnode->setAttribute("name", $row['name']);
$newnode->setAttribute("address", $row['address']);
$newnode->setAttribute("lat", $row['lat']);
$newnode->setAttribute("lng", $row['lng']);
$newnode->setAttribute("distance", $row['distance']);
}
echo $dom->saveXML();
?>
这肯定能解决你的问题。
如果您想要完整的商店定位器代码，请写下注释。