mySQL查询需要计数到不同的字段,其中一个字段为1


mySQL query needs to count to different fields where one field is 1

我需要从数据库的多个表中获取数据,并且需要使用一个查询。我遇到的麻烦是,我需要计算每个项目有多少任务,以及完成了多少任务。

我有这些桌子:
项目:

id    name        start_date           end_date             project_leader    finished
1     project_1   2012-08-01 00:00:00  2012-29-01 00:00:00  2                 0

用户

id    username    password    email      status
1     user_1      pass_1      email_1    1
2     user_2      pass_2      email_2    1

user_has_project

userid   projectId
1        1

任务

id   project  description          end_date               user  finished
1    1        test description 1   2012-29-01 00:00:00    1     1
2    1        test description 2   2012-29-01 00:00:00    1     0

因此,我需要做的是生成一个查询,该查询应给出以下结果:
想要的结果:

project_id  project_name    start_date           end_date             project_leader    finished       tasks      finished_tasks
1           project_1       2012-08-01 00:00:00  2012-29-01 00:00:00  user_2            0              2          1

我让它一直工作到我需要计算完成任务数量的部分。到目前为止,我收到了这个查询,但它还没有计算完成的任务。我该怎么做?

查询:

SELECT projects.id,
       projects.name,
       projects.start_date,
       projects.end_date,
       projects.finished,
       users.username AS project_leader,
       COUNT(tasks.id) AS tasks
FROM projects
LEFT JOIN tasks ON (tasks.project = projects.id)
JOIN user_has_project ON (user_has_project.projectId = projects.id)
JOIN users ON (projects.project_leader = users.id)
WHERE user_has_project.userId = 1
GROUP BY projects.id

我在这里有点草率(我会继续考虑,以防这种直觉反应是错误的),但诀窍可能是在count()函数中使用"如果为false,则为null"的评估,该函数被记录为只计算非null值:

SELECT projects.id,
       projects.name,
       projects.start_date,
       projects.end_date,
       projects.finished,
       users.username AS project_leader,
       COUNT(tasks.id) AS tasks,
       COUNT(NULLIF(tasks.finished, 0)) as finished_tasks