为什么findone()将所有公共属性返回为null。
class User extends 'yii'db'ActiveRecord
{
public $id;
public $username;
public $password;
public $authKey;
public $accessToken;
/**
* Finds user by username
*
* @param string $username
* @return static|null
*/
public static function findByUsername($username)
{
$result = static::findOne(['username' => $username]);
var_dump($result);
return $result;
}
这将返回
object(app'models'User)[81]
public 'id' => null
public 'username' => null
public 'password' => null
public 'authKey' => null
public 'accessToken' => null
private '_attributes' (yii'db'BaseActiveRecord) =>
array (size=6)
'id' => int 1
'username' => string 'admin' (length=5)
'password' => string '123456' (length=6)
'auth_key' => string 'jkkk' (length=4)
'created' => null
'modified' => null
您应该简单地从模型中删除数据库属性:
class User extends 'yii'db'ActiveRecord
{
public static function findByUsername($username)
{
....
Yii自动在活动记录中为关联表的每一列定义一个属性您不应该重新声明任何属性。
阅读更多:http://www.yiiframework.com/doc-2.0/guide-db-active-record.html