如何在php中编写mysql用户定义函数


How to write mysql user defined function in php

请告诉我如何在PHP中定义MySQL用户定义函数。。。

我正在使用以下代码。但它不起作用。

它抛出错误:

"(1313)仅在FUNCTION"中允许返回

$mysqli = new mysqli( $DBHost, $DBUserName, $DBPassword, $DBName );

$Query =
"CREATE PROCEDURE FunGetRegistryValue(OUT Param_RegistryKey varchar(40))
BEGIN
    DECLARE vResult varchar(90);
    SELECT  iFnull(Value,'') INTO vResult FROM Project_Registry Where RegistryKey=Param_RegistryKey;
    RETURN(vResult);
END;";
if( !$mysqli->query( $Query ) ) {
    echo "Stored procedure creation failed: (" . $mysqli->errno . ") " . $mysqli->error;
}

当我使用FUNCTION关键字而不是PROCEDURE时,我会出现语法错误。。。

请给我"VALUE RETURNING FUNCTION"的示例代码

DELIMITER $$ 
CREATE DEFINER=root@localhost
FUNCTION FunGetRegistryValue(Param_RegistryKey varchar(40)) 
RETURNS varchar(90) 
CHARSET latin1 DETERMINISTIC 
BEGIN 
    DECLARE vResult varchar(90); 
    SELECT iFnull(Value,'') INTO vResult 
    FROM Project_Registry Where RegistryKey=Param_RegistryKey;
    RETURN(vResult); 
END$$ 
DELIMITER ;

最初是福齐亚的评论。我添加它作为一个答案,这样它就不会是一个混乱的运行查询,并且清晰易读。

$mysqli=new mysqli($DBHost,$DBUserName,$DBPassword,$DBName);

$Query =
"DROP FUNCTION IF EXISTS FunGetRegistryValue;
CREATE   FUNCTION FunGetRegistryValue(Param_RegistryKey VARCHAR(40)) RETURNS VARCHAR(90) CHARSET latin1
   DETERMINISTIC
BEGIN
   DECLARE vResult VARCHAR(90);
   SELECT  IFNULL(VALUE,'') INTO vResult FROM Project_Registry WHERE RegistryKey=Param_RegistryKey;
   RETURN(vResult);
   END;";
if( !$mysqli->multi_query( $Query ) ) {
    echo $mysqli->error;
    exit();
}