我正在阅读一本书中关于二进制数据的一章。我想做的是在我的数据库处理个人资料时自动显示一个人的照片。
到目前为止，我的解决方案是有效的，照片是拼图的最后一块。
这本书会把文件名链接输出到屏幕上，点击这个链接就会显示图片。
我想做的不是这样，而是让图片自动显示，比如在Facebook上。在那里，你不会看到你的个人资料图片的链接，而是实际图片本身。
代码如下：
INDEX.PHP（控制器）
<?php
include_once $_SERVER['DOCUMENT_ROOT'] . '/includes/magicquotes.inc.php';
if (isset($_POST['action']) and $_POST['action'] == 'upload')
{
// Bail out if the file isn't really an upload
if (!is_uploaded_file($_FILES['upload']['tmp_name']))
{
$error = 'There was no file uploaded!';
include $_SERVER['DOCUMENT_ROOT'] . '/includes/error.html.php';
exit();
}
$uploadfile = $_FILES['upload']['tmp_name'];
$uploadname = $_FILES['upload']['name'];
$uploadtype = $_FILES['upload']['type'];
$uploaddesc = $_POST['desc'];
$uploaddata = file_get_contents($uploadfile);
include 'db.inc.php';
try
{
$sql = 'INSERT INTO filestore SET
filename = :filename,
mimetype = :mimetype,
description = :description,
filedata = :filedata';
$s = $pdo->prepare($sql);
$s->bindValue(':filename', $uploadname);
$s->bindValue(':mimetype', $uploadtype);
$s->bindValue(':description', $uploaddesc);
$s->bindValue(':filedata', $uploaddata);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Database error storing file!';
include $_SERVER['DOCUMENT_ROOT'] . '/includes/error.html.php';
exit();
}
header('Location: .');
exit();
}
if (isset($_GET['action']) and
($_GET['action'] == 'view' or $_GET['action'] == 'download') and
isset($_GET['id']))
{
include 'db.inc.php';
try
{
$sql = 'SELECT filename, mimetype, filedata
FROM filestore
WHERE id = :id';
$s = $pdo->prepare($sql);
$s->bindValue(':id', $_GET['id']);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Database error fetching requested file.';
include $_SERVER['DOCUMENT_ROOT'] . '/includes/error.html.php';
exit();
}
$file = $s->fetch();
if (!$file)
{
$error = 'File with specified ID not found in the database!';
include $_SERVER['DOCUMENT_ROOT'] . '/includes/error.html.php';
exit();
}
$filename = $file['filename'];
$mimetype = $file['mimetype'];
$filedata = $file['filedata'];
$disposition = 'inline';
if ($_GET['action'] == 'download')
{
$mimetype = 'application/octet-stream';
$disposition = 'attachment';
}
// Content-type must come before Content-disposition
header('Content-length: ' . strlen($filedata));
header("Content-type: $mimetype");
header("Content-disposition: $disposition; filename=$filename");
echo $filedata;
exit();
}
if (isset($_POST['action']) and $_POST['action'] == 'delete' and
isset($_POST['id']))
{
include 'db.inc.php';
try
{
$sql = 'DELETE FROM filestore
WHERE id = :id';
$s = $pdo->prepare($sql);
$s->bindValue(':id', $_POST['id']);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Database error deleting requested file.';
include $_SERVER['DOCUMENT_ROOT'] . '/includes/error.html.php';
exit();
}
header('Location: .');
exit();
}
include 'db.inc.php';
try
{
$result = $pdo->query(
'SELECT id, filename, mimetype, description
FROM filestore');
}
catch (PDOException $e)
{
$error = 'Database error fetching stored files.';
include $_SERVER['DOCUMENT_ROOT'] . '/includes/error.html.php';
exit();
}
$files = array();
foreach ($result as $row)
{
$files[] = array(
'id' => $row['id'],
'filename' => $row['filename'],
'mimetype' => $row['mimetype'],
'description' => $row['description']);
}
include 'files.html.php';
PHOTO.HTML（查看）
<?php include_once $_SERVER['DOCUMENT_ROOT'] . '/includes/helpers.inc.php'; ?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>PHP/MySQL File Repository</title>
</head>
<body>
<h1>PHP/MySQL File Repository</h1>
<form action="" method="post" enctype="multipart/form-data">
<div>
<label for="upload">Upload File:
<input type="file" id="upload" name="upload"></label>
</div>
<div>
<label for="desc">File Description:
<input type="text" id="desc" name="desc" maxlength="255"></label>
</div>
<div>
<input type="hidden" name="action" value="upload">
<input type="submit" value="Upload">
</div>
</form>
<?php if (count($files) > 0): ?>
<p>The following files are stored in the database:</p>
<table>
<thead>
<tr>
<th>Filename</th>
<th>Type</th>
<th>Description</th>
</tr>
</thead>
<tbody>
<?php foreach($files as $f): ?>
<tr>
<td>
<a href="?action=view&id=<?php htmlout($f['id']); ?>"
><?php htmlout($f['filename']); ?></a>
</td>
<td><?php htmlout($f['mimetype']); ?></td>
<td><?php htmlout($f['description']); ?></td>
<td><?php htmlout($f['filedata']); ?></td>
<td>
<form action="" method="get">
<div>
<input type="hidden" name="action" value="download"/>
<input type="hidden" name="id" value="<?php htmlout($f['id']); ?>"/>
<input type="submit" value="Download"/>
</div>
</form>
</td>
<td>
<form action="" method="post">
<div>
<input type="hidden" name="action" value="delete"/>
<input type="hidden" name="id" value="<?php htmlout($f['id']); ?>"/>
<input type="submit" value="Delete"/>
</div>
</form>
</td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
<?php endif; ?>
</body>
</html>
感谢所有的帮助。
当前照片摘录.HTML
<?php foreach($files as $f): ?>
<tr>
<td>
<a href="?action=view&id=<?php htmlout($f['id']); ?>"
><?php htmlout($f['filename']); ?></a>
<!-- attempt to output image not path -->
<img src="<?php echo htmlout($f['filename']); ?>" />
</td>
辅助功能
<?php
function html($text)
{
return htmlspecialchars($text, ENT_QUOTES, 'UTF-8');
}
function htmlout($text)
{
echo html($text);
}
?>
将其包装在<img>标记中。这将把它作为图像输出。
即<img src="<?php echo $image; ?>">
在大多数情况下，将图像文件保存在通过HTTP公开的目录结构中的某个位置，并将指向该图像位置的链接存储在数据库中，会更好地为您服务。
因此，例如，当用户上传图像时，您将其放在web目录中的某个用户图像目录中，然后将图像的路径或URL存储在数据库中的varchar字段中。
这使您可以降低数据库大小，使您从数据库中查询图片信息的速度更快，改善图像的浏览器缓存，并允许您将静态文件保存在一个位置（可能再次在CDN上，以便在最终用户的浏览器中获得更好的性能）。