如何通过FTP保存图像？这是我的代码：
$conn_id = ftp_connect('***');
$login_result = ftp_login($conn_id, '***','***');
if( $login_result) echo 'connected';
$save = "FTP://temp/". $FileName;
imagepng($this->Picture, $save);
/*if (ftp_put($conn_id,$save,$save, FTP_ASCII))
echo "successfully uploaded 'n";
else
echo "There was a problem while uploading 'n";
*/
你可以做：
ob_start();
imagepng($this->Picture);
$image = ob_get_clean();
$stream = stream_context_create(array('ftp' => array('overwrite' => true)));
file_put_contents("ftp://user:pass@host/folder/".$FileName, $image, 0, $stream);
希望这能帮助您
<?
//Configuration
$ftp_server = "ftpaddress";
$ftp_user = "username";
$ftp_pass = "password";
// set up a connection or die
$conn_id = ftp_connect($ftp_server) or die("Couldn't connect to $ftp_server");
//trying to connect with login details
if (@ftp_login($conn_id, $ftp_user, $ftp_pass)) {
echo "Connected! ";
} else {
echo "Couldn't connect!";
}
//You can change it with the file name, this is for if you're upload using form.
$myName = $_POST['name']; //This will copy the text into a variable
$myFile = $_FILES['file_name']; // This will make an array out of the file information that was stored.
?>
<?PHP
$destination_path = "dest/path/";
//your desired path for uploading)
$destination_file = $destination_path."img.jpg";
//This will create a full path with the file on the end for you to use, I like splitting the variables like this in case I need to use on on their own or if I'm dynamically creating new folders.
$file = $myFile['tmp_name'];
//Converts the array into a new string containing the path name on the server where your file is.
$upload = ftp_put($conn_id, $destination_file, $file, FTP_BINARY);// upload the file
if (!$upload) {// check upload status
echo "FTP upload of $destination_file has failed!";
} else {
echo "Uploaded $file to $conn_id as $destination_file";
}
?>