使用带参数的URL在Swift中更新远程数据库中的记录 - Update a record from remote database in Swift using URL with parameter

Update a record from remote database in Swift using URL with parameter

我想在url中传递一个整数参数来更新远程数据库中记录的字段，但我遇到了错误。如何做到这一点？我的php可以工作，但如果从Swift调用就不行。如何在Swift中执行用于更新数据库记录的php文件？

下面是服务器上用于更新记录的php。如何从Swift应用程序运行此程序？在网络上，我这样做，它运行（IdTask是唯一的）：

http://.../updateonetasktocompleted.php?x=2

<?php
$host = "localhost"; //database host server
$db = "dbname"; //database name
$user = "dbuser"; //database user
$pass = "passwd"; //password
$connection = mysql_connect($host, $user, $pass);
//Check to see if we can connect to the server
if(!$connection)
{
die("Database server connection failed.");  
}
else
{
//Attempt to select the database
$dbconnect = mysql_select_db("dbname", $connection);
//Check to see if we could select the database
if(!$dbconnect)
{
    die("Unable to connect to the specified database!");
}
else
{
    $idtask_selected = $_GET['x'];
    $query = "UPDATE ProtocolSets_Protocols SET `ProtocolSets_Protocols`.`Completed`='Yes' WHERE `ProtocolSets_Protocols`.`IdTask`= $idtask_selected";        
    $resultset = mysql_query($query, $connection);
    echo "Successfully added ";
    echo $query;
}
}
?>

如果您试图从Swift代码中运行命令行php脚本，可以使用NSTask:

var task = NSTask()
task.launchPath = "/path/to/your/script/script.php"
task.arguments = ["25"]
task.launch()

但我可能误解了你的问题，因为你没有提供太多上下文。

我找到了一种方法：

let currentIdTask:Int? = NSUserDefaults.standardUserDefaults().stringForKey("selectedIdTask")?.toInt()
var url: NSString = "http://.../updateonetasktocompleted.php?x='(currentIdTask!)"
url = url.stringByReplacingOccurrencesOfString(" ", withString: "%20")
url = url.stringByReplacingOccurrencesOfString("/n", withString: "%0A")
println(url)
var data = NSData(contentsOfURL: NSURL(string: url)!)
var result = NSString(data: data!, encoding: NSUTF8StringEncoding)
println(result)