我有一个包含PHP生成选项的下拉列表。我正在尝试捕获所选的值，因为我需要将其传递给另一个函数。通常情况下，$_POST['patient_dropdown']可以正常工作，但我无法使其适用于我的情况。是否有任何方法可以将所选值捕获到中
<select name="patient_dropdown" id="patient_dropdown" class="patientform">
<?php
$response = "";
$client = new SoapClient("healthinfosys.wsdl");
$response = $client->getAllPatientsEntry();
echo $response;
?>
</select>
供您参考，以下是用于生成下拉菜单选项的函数-
function getAllPatientsEntry(){
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "healthinfosys";
//Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
//Check connection
if($conn->connect_error){
die("Connection failed " . $conn->connect_error);
}
$sql = "SELECT * FROM patient_info";
$result = $conn->query($sql);
if($result->num_rows > 0){
//Output data of each row
while($row = $result->fetch_assoc()){
$output = $output . "<option value='"'">".$row['patient_name']."</option>";
}
}
else{
echo "0 results";
}
$conn->close();
return $output;
}
您需要为您的选项分配一个值：
while($row = $result->fetch_assoc()){
$output = $output.'<option value="'.$row['patient_name'].'">'.$row['patient_name']."</option>";
// or $row['patient_id'] or something else
}
您必须为您的选项分配一个值，如下所示您的代码有问题
//Output data of each row
while($row = $result->fetch_assoc()){
$output = $output . "<option value='"'">".$row['patient_name']."</option>";
}
更改为此
//Output data of each row
while($row = $result->fetch_assoc()){
$output = $output . "<option value='".$row['patient_name']."'>".$row['patient_name']."</option>";
}