从php脚本调用中获取响应

您可以尝试修改您的PHP代码。下面是一个评论良好的示例代码，让你开始：

    <?php
        // EXPLICITLY INSTRUCT THE HEADER ABOUT THE CONTENT TYPE. HERE - JSON 
        header('Content-type: application/json');
        if($_POST["mode"]=="newuser"){
            $gcmRegID       = htmlspecialchars(trim($_POST["regID"]));
            $gcmUserName    = htmlspecialchars(trim($_POST["userName"]));
            $gcmFolderName  = htmlspecialchars(trim($_POST["folderName"]));
            $gcmDate        = date("d/m/y");
            // I WOULD STRONGLY SUGGEST YOU USE PDO FOR YOUR DATABASE TRANSACTIONS:
            // HERE'S HOW:
            //DATABASE CONNECTION CONFIGURATION:
            defined("HOST")     or define("HOST",   "localhost");           //REPLACE WITH YOUR DB-HOST
            defined("DBASE")    or define("DBASE",  "database");            //REPLACE WITH YOUR DB NAME
            defined("USER")     or define("USER",   "root");                //REPLACE WITH YOUR DB-USER
            defined("PASS")     or define("PASS",   "root");                //REPLACE WITH YOUR DB-PASS
            // ESTABLISH A CONNECTION AND DO YOUR WORK WITHIN A TRY-CATCH BLOCK...
            try {
                $dbh        = new PDO('mysql:host='.HOST.';dbname='. DBASE,USER,PASS);
                $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
                // HERE: ALL YOUR BUSINESS LOGIC...
                $in_user        = "user";
                $in_password    = "NULL";
                $in_email       = "NULL";
                $in_phone       = "NULL";
                $in_dob         = "NULL";
                $in_role        = "user";
                $in_dateJoined  = "0000-00-00";
                $folderName     = "NULL";
                $insertSQL      = "INSERT INTO user(`password`, `regid`, `name`, `email`, `phone`, `dob`, `role`, `datejoined`, `foldername`) ";
                $insertSQL     .= " VALUES(:inPassword, :gcmRegID, :gcmUserName, :inEmail, :inPhone, :inDOB, :inRole, :gcmDate, :folderName)";
                $arrInsertData  = array(
                    'inPassword'    => $in_password,
                    'gcmRegID'      => $gcmRegID,
                    'gcmUserName'   => $gcmUserName,
                    'inEmail'       => $in_email,
                    'inPhone'       => $in_phone,
                    'inDOB'         => $in_dob,
                    'inRole'        => $in_role,
                    'gcmDate'       => $gcmDate,
                    'folderName'    => $folderName
                );
                // PREPARE THE INSERT QUERY:
                $insertStmt = $dbh->prepare($insertSQL);
                // INSERT THE NEW ROW:
                $insertStmt->execute($arrInsertData);
                // OBTAIN THE ID OF THE INSERTED ROW TO BE USED AS SUFFIX FOR YOUR USER FOLDER
                $id         = $dbh->lastInsertId();
                // WHAT HAPPENS WHEN 2 USERS HAVE THE SAME USERNAME??? DID YOU THINK ABOUT THAT?
                // TO CIRCUMVENT THIS ISSUE; I WOULD SUGGEST FIRST TO INSERT THE DATA TO THE DATABASE...
                // THEN USE THE ID AS A SUFFIX TO MAKE EACH USER DIRECTORY UNIQUE & THAT IS THE APPROACH TAKEN HERE THOUGH...
                // NOW YOU CAN CREATE YOUR FOLDER USING THIS ID: $id
                // LIKE THIS; 2 USERS WITH USERNAME "android_user" CAN HAVE 2 DIFFERENT FOLDERS LIKE SO: "android_user_97" & "android_user_102"
                $userDirectory  = "./users/" . $gcmFolderName . "_" . $id;
                mkdir($userDirectory);
                // DID IT OCCUR TO YOU THAT 2 USERS MIGHT HAVE THE SAME USERNAME IN WHICH CASE MYSQL (INSTEAD OF YOU) HAS TO DECIDE WHICH USER TO UPDATE?
                // THAT IS WHY DATABASE TABLES ARE DESIGNED TO HAVE UNIQUE IDENTIFIERS LIKE UUID OR ID OR UID OR ANY TOKEN TO MAKE EACH ROW UNIQUE...
                // WE ARE ADOPTING THIS APPROACH IN THE UPDATE QUERY... THAT IS: WE UPDATE THE ROW USING THE ID ABOVE... ASSUMING THAT IS A UNIQUE COLUMN THOUGH.
                $updateSQL      = "UPDATE user SET foldername=:newDirName WHERE id=:ID";
                // NOW UPDATE THE ROW TO TAKE INTO ACCOUNT THE UNIQUE USER-DIRECTORY (USING THE ID AS THE KEY)
                $arrUpdateData  = array(
                    'newDirName'    => $userDirectory,
                    'ID'            => $id      // THIS ASSUMES THAT THE PRIMARY KEY OF YOUR TABLE IS CALLED id OTHERWISE USE THE APPROPRIATE KEY NAME: EG: reg_id OR WHATEVER
                );
                // PREPARE THE UPDATE QUERY:
                $insertStmt = $dbh->prepare($updateSQL);
                // UPDATE THE NEWLY CREATED ROW:
                $insertStmt->execute($arrUpdateData);
                // BUILD THE RESPONSE JSON DATA
                $arrResponse    = array(
                    'folderName'    => $userDirectory,
                    'id'            => $id,
                );
                // SEND THE RESPONSE AS JSON IF ALL WORKS FINE TILL HERE... 
                // THAT MEANS: SEND THE DATA IN $arrResponse AND TERMINATE THE SCRIPT - THE JOB IS DONE.
                // NO NEED FOR ALL THOSE ECHO STATEMENTS AS THE YOU ARE EXPLICITLY SENDING BACK JSON DATA.
                die( json_encode($arrResponse) );
            }catch(PDOException $e){
                // IF THERE WAS ANY KIND OF PDO ERROR, SEND IT BACK ANYWAYS - BUT ALSO AS JSON:             
                $arrResponse    = array(
                    'error'     => $e->getMessage()
                );
                die( json_encode($arrResponse) );
            }
        }

我现在不能测试代码（抱歉），但我认为应该是这样的：

try {
    RequestParams rParams = new RequestParams();
    rParams.put("example", "example"); // POST
    AsyncHttpClient client = new AsyncHttpClient();
    client.get(pageURL, rParams, new JsonHttpResponseHandler() {
        @Override
        public void onSuccess(JSONArray jsonArray) {
            super.onSuccess(jsonArray);
            //process JSON Array
        }
        @Override
        public void onFailure(Throwable throwable, JSONArray jsonArray) {
            super.onFailure(throwable, jsonArray);
            Log.d(TAG, "error", throwable);
        }
    });
} catch (Exception e) {
    Log.d(TAG, "exception", e);
}

否则我做了一个非常轻的WebClient，你可能想试试：

https://github.com/omaflak/WebClient

这是一个简短的示例：

WebClient client = new WebClient();
client.setOnRequestListener(new OnRequestListener() {
        @Override
        public void onRequest(String response, int requestID) {
            Log.e(TAG, response);
        }
        @Override
        public void onError(int error_code, String message) {
            Log.e(TAG, message);
        }
});
Pair p = new Pair("field1", "value1");
Pair p2 = new Pair("field2", "value2");
client.requestAsync("http://your-api.com", WebClient.POST, Arrays.asList(p, p2), 1);
//  requestAsync(String url, String method, List<Pair<String, String>> postData, int requestID)

要使用它，只需添加到您的依赖项：

compile 'me.aflak.libraries:webclient:1.0'