我有一个数组,看起来像这样:
Array (
[0] => Array ( [country_percentage] => 5 %North America )
[1] => Array ( [country_percentage] => 0 %Latin America )
)
我只想要上面数组中的数值。我想要我的最后一个阵列像这个
Array (
[0] => Array ( [country_percentage] => 5)
[1] => Array ( [country_percentage] => 0)
)
我是如何使用PHP实现这一点的??提前感谢。。。
当数字位于第一个位置时,可以像这样进行int强制转换:
$newArray = [];
foreach($array => $value) {
$newArray[] = (int)$value;
}
我想您可以循环二维数组并使用preg_replace
,即:
for($i=0; $i < count($arrays); $i++){
$arrays[$i]['country_percentage'] = preg_replace( '/[^'d]/', '', $arrays[$i]['country_percentage'] );
}
Ideone演示
根据您的评论更新:
for($i=0; $i < count($arrays); $i++){
if( preg_match( '/North America/', $arrays[$i]['country_percentage'] )){
echo preg_replace( '/[^'d]/', '', $arrays[$i]['country_percentage'] );
}
}
试试这个:
$arr = array(array('country_percentage' => '5 %North America'),array("country_percentage"=>"0 %Latin America"));
$result = array();
foreach($arr as $array) {
$int = filter_var($array['country_percentage'], FILTER_SANITIZE_NUMBER_INT);
$result[] = array('country_percentage' => $int);
}
试试这个:-
$arr =[['country_percentage' => '5 %North America'],
['country_percentage' => '0 %Latin America']];
$res = [];
foreach ($arr as $key => $val) {
$res[]['country_percentage'] = (int)$val['country_percentage'];
}
echo '<pre>'; print_r($res);
输出:-
Array
(
[0] => Array
(
[country_percentage] => 5
)
[1] => Array
(
[country_percentage] => 0
)
)
您可以使用array_walk_recursive
来消除循环,
传递回调的第一个参数作为修改初始数组值的引用
然后应用filter_var
或intval
,如前面提到的其他答案。
$array = [
["country_percentage" => "5 %North America"],
["country_percentage" => "0 %Latin America"]
];
array_walk_recursive($array, function(&$value,$key){
$value = filter_var($value,FILTER_SANITIZE_NUMBER_INT);
// or
$value = intval($value);
});
print_r($array);
将输出
Array
(
[0] => Array
(
[country_percentage] => 5
)
[1] => Array
(
[country_percentage] => 0
)
)
您可以通过循环遍历数组来获得所有nemeric值。然而,我不认为这是最有效和好看的答案,我无论如何都会发布它。
// Array to hold just the numbers
$newArray = array();
// Loop through array
foreach ($array as $key => $value) {
// Check if the value is numeric
if (is_numeric($value)) {
$newArray[$key] = $value;
}
}
我误解了你的问题。
$newArray = array();
foreach ($array as $key => $value) {
foreach ($value as $subkey => $subvalue) {
$subvalue = trim(current(explode('%', $subvalue)));
$newArray[$key] = array($subkey => $subvalue);
}
}
如果您想要除数值以外的所有值:
$array[] = array("country_percentage"=>"5 %North America");
$array[] = array("country_percentage"=>"3 %Latin America");
$newArray = [];
foreach ($array as $arr){
foreach($arr as $key1=>$arr1) {
$newArray[][$key1] = intval($arr1);
}
}
echo "<pre>";
print_R($newArray);
这是一种简单的方法,因为我喜欢使用尽可能多的预制函数。但这应该对你有效:D
$array = array('jack', 2, 5, 'gday!');
$new = array();
foreach ($array as $item) {
// IF Is numeric (each item from the array) will insert into new array called $new.
if (is_numeric($item)) { array_push($new, $item); }
}