我有一个代码:
$id=implode(",",$selected);
$query = "SELECT u.id, p.brand, n.number FROM `user` u
LEFT OUTER JOIN `phone` p ON u.id = p.id LEFT OUTER JOIN `number` n
ON p.id = n.id WHERE u.id in ($id)";
其中$selected是一个数组array(1,2,3)
。但当我运行它时,它出现了这样的通知:
"where子句"中的未知列"1"
如何处理这个问题?感谢
在这里你可以这样做:
$id = implode("','",$selected);
此查询将运行:
$query = "SELECT u.id, p.brand, n.number FROM `user` u LEFT OUTER JOIN `phone` p ON u.id = p.id LEFT OUTER JOIN `number` n
ON p.id = n.id WHERE u.id in ('$id')";