我有数据库结构
id | ref_id |舒适度1 |舒适度2 |舒适度3 |舒适度4 |舒适度5
每个舒适度列的值为1或0。进行搜索时，我需要显示值不等于零（值！=0）的字段。我知道我可以在VIEW中作为来做这件事
if($data->amenity1 == 0) echo '';
但我需要它是有限度的自动化。
我的MODEL代码是
function select_all_active_amenities($for_id){
foreach($for_id as $id){
$prop_id = $id->vbc_item_id;
}
$this->db->select('*');
$this->db->from('vbc_property_amenities');
$this->db->where_in(array('v_ref_id'=> $prop_id));
$this->db->limit(5);
$query = $this->db->get();
$result = $query->result();
return $result;
}
请帮助
在Select之前将"DISTINCT"关键字添加到查询中，以获得唯一的记录
$this->db->distinct();
希望它能帮助你！
您只需使用自定义数组构建来删除空列
function select_all_active_amenities($for_id){
foreach($for_id as $id){
$prop_id = $id->vbc_item_id;
}
$this->db->select('*');
$this->db->distinct('v_ref_id');
$this->db->from('vbc_property_amenities');
$this->db->where_in(array('v_ref_id'=> $prop_id));
// $this->db->limit(5);
$query = $this->db->get();
$result1 = $query->result_array();
//fetch the value as array
//and this query for fetch the column name what you have right now an where not equal to id and ref_id
$this->db->query("SELECT COLUMN_NAME FROM information_schema.COLUMNS WHERE TABLE_NAME='vbc_property_amenities' AND COLUMN_NAME !='id' AND COLUMN_NAME != 'ref_id AND COLUMN_NAME !='id' ")->result_array();
$query = $this->db->get();
$result2 = $query->result_array();
foreach($result as $key1=>$row1)
{
foreach($result2 as $key2=>$row2)
{
if($row2 ==$row1[$row2] && $row1 ==0)
{
unset($result[$key1][$row2]);
}
}
}
//$result only have the where value=1
return $result;
//you just limit the five in your view page
}