通过用于气泡图的PHP将SQL处理为JSON


Process SQL to JSON through PHP for Bubble Chart

我正在使用Highcharts制作气泡图。这是我的数据样本:

  name  | price | quantity | count
--------+-------+----------+-------
 Female |     2 |        3 |     5
 Female |     3 |       12 |    10
 Female |     5 |        6 |    15
 Female |     1 |        7 |    25
 Male   |     3 |        5 |     7
 Male   |     2 |        9 |    11
 Male   |     5 |        7 |    23
 Male   |     4 |        4 |    14

我使用PHP查询数据并编码为JSON:

$query = "SELECT name, price, quantity, count FROM sales WHERE id = $1";
$result = pg_prepare($db, "report", $query);
$result = pg_execute($db, "report", array($ID));
while ($row = pg_fetch_array($result, NULL, PGSQL_ASSOC))
{
        $response['xdata'][$row['name']]['x'][] = $row['price'];
        $response['xdata'][$row['name']]['y'][] = $row['quantity'];
        $response['xdata'][$row['name']]['radius'][] = $row['count'];
}
echo json_encode($response);

然而,为了正确绘制图形,所需的JSON格式如下:

series: [{
    name: 'Female',
    marker:{
        symbol:'circle',
        fillColor:'rgba(24,90,169,.5)',
        lineColor:'rgba(24,90,169,.75)',
        lineWidth:1,
        color:'rgba(24,90,169,1)',
        states:{
            hover:{
                enabled:false
            }
        }
    },
    data: [{x:2,y:3,marker:{radius:5}},
           {x:3,y:12,marker:{radius:10}},
           {x:5,y:6,marker:{radius:15}},
           {x:1,y:7,marker:{radius:25}}]
    },{
    name: 'Male',
    marker:{
        symbol:'circle',
        fillColor:'rgba(238,46,47,.5)',
        lineColor:'rgba(238,46,47,.75)',
        lineWidth:1,
        color:'rgba(238,46,47,1)',
        states:{
            hover:{
                enabled:false
            }
        }
    },
    data: [{x:3,y:5,marker:{radius:7}},
           {x:2,y:9,marker:{radius:11}},
           {x:5,y:7,marker:{radius:23}},
           {x:4,y:4,marker:{radius:14}}]
   }]

我的问题是,如何在PHP中正确处理$query,以获得如上所述的所需JSON格式,并通过类似optionsBubble.series = data.xdata的东西将其传递给series?非常感谢!

您首先必须将非数据库相关的部分构建到PHP结构中,例如

$data = array(
   0 => array(
        'name' => 'Female',
        'marker' => array (
             'symbol': 'circle'
             etc....),
        'data' => array() // database insertion occurs here
        ),
   1 => array(
        'name' => 'Male',
        etc...
        )
);
$locations = array('Female' => 0, 'Male' => 1, etc...) // reverse map your 'name' fields
while(...) {
     $data[$locations[$row['name']]][data]['x'][] = $row['price'];
     $data[$locations[$row['name']]][data]['y'][] = $row['quantity'];
           ^^^^^^^^^^^^^^^^^^^^^^^^--- reverse lookup to get right array index for 'name'
}

首先,我建议您查看SQL查询,尤其是WHERE id=$1部分。如果我没有错的话(在这一点上,我相当确定。)您的查询将返回一(1)行,这与您可能想要的不太一样。我建议删除WHERE子句,看看这是否能解决您的问题。

如果不给我写信,我会看看我还能看到什么,我们可以从那里出发。