PHP.为什么返回包含的文件dosen'；t用变量赋值 - PHP. Why return in included file dosen't assign with variable?

PHP. Why return in included file dosen't assign with variable?

例如，我有两个文件：

//db.php
return array(
   'server'=>'localhost',
   'db'=>'mydb',
   'name'=>'root',
   'password'=>'root',
);

和第二个文件：

//index.php
$config = (include 'db.php');

之后，如果包含文件，则为$config = 1，如果不包含文件，那么为$config = 0，但$config必须是db.php文件中的array()。

什么问题？

windows 7x64、apache 2.2、php 5.4

您可以使用INI文件作为DB凭据。不要忘记拒绝访问.htaccess文件中的config.ini。

config.ini

[database]
server = localhost
db = mydb
name = root
password = root

index.php

<?php
    $config = parse_ini_file('config.ini');
    // Access to credentials
    echo $config['server'];
?>

来自decze的真实答案短开放标签！！！

<? The array is not supposed to be output at all; if it is, something's wrong with your file. In this case, PHP isn't configured to handle short open tags