这里我有一个代码,比如从index.php获取数据,如果用户输入数据,它将显示为类似表格的数据,并且应该通过电子邮件发送到一些预定义的邮件。但在这里,我动态地获取数据,我尝试了$_REQUEST和$_POST这两种方法来获取数据,但在邮件函数中,我试图更改消息参数,但通过php标记,它没有获取并显示一些语法错误。
请检查一下这里的代码
<?php
$to="xxxxxxx@gmail.com";
$fn="Fisrt Name";
$ln="Last Name";
$name=$fn.' '.$ln;
$from="xxxxx@xxx.com";
$subject = "Welcome to Website";
include('newsmtp/smtpwork.php');
?>
<?php
$message = 'Dear $firstName,
Your Welcome Message.'.'
<table border=1>
<tr>
<td>First Name:</td>
<td><?php $firstName=$_POST['firstname'];
echo $firstName;?></td>
</tr>
<tr>
<td>Last Name:</td>
<td><?php $lastname=$_POST['lastname'];
echo $lastname;?></td>
</tr>
<tr>
<td>Title:</td>
<td><?php $title=$_POST['title'];
echo $title;?></td>
</tr>
<tr>
<td>Address:</td>
<td><?php $address=$_POST['address'];
echo $address;?></td>
</tr>
<tr>
<td>Phone Number:</td>
<td><?php $phone=$_POST['phone'];
echo $phone;?></td>
</tr>
<tr>
<td>Course Name:</td>
<td><?php $course=$_POST['coursename'];
echo $course;?></td>
</tr>
<tr>
<td>Website:</td>
<td><?php $website=$_POST['website'];
echo $website;?></td>
</tr>
</table>
Thanks
xxxxxxxxxxxx
';
?>
尝试此方法,在$message变量外部的变量中分配已发布的值,并在$message变量中打印该变量
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$title = $_POST['title'];
$address = $_POST['address'];
$phone = $_POST['phone'];
$course = $_POST['course'];
$website = $_POST['website'];
$message = 'Dear '.$firstName.',
Your Welcome Message.'.'
<table border=1>
<tr>
<td>First Name:</td>
<td>'.$firstname.' </td>
</tr>
<tr>
<td>Last Name:</td>
<td>'.$lastname.'</td>
</tr>
<tr>
<td>Title:</td>
<td>'.$title.'</td>
</tr>
<tr>
<td>Address:</td>
<td>'.$address.'</td>
</tr>
<tr>
<td>Phone Number:</td>
<td>'.$phone.'</td>
</tr>
<tr>
<td>Course Name:</td>
<td>'.$course.'</td>
</tr>
<tr>
<td>Website:</td>
<td>'.$website.'</td>
</tr>
</table>
Thanks
xxxxxxxxxxxx
';
?>
$to ="xxxxxxx@gmail.com";
$subject = "Welcome to Website";
$headers = 'From: xxxxxx <noreply@xxxxxxx.com>' . "'r'n";
$headers .= "MIME-Version: 1.0'r'n";
$headers .= "Content-Type: text/html;'n'tcharset='"iso-8859-1'"'r'n";
$sent = @mail($to,$subject,$message,$headers);
if ($sent) {
return true;
} else {
return false;
}
此外,添加必要的标题以发送HTML邮件,如Vinoth Babu,Naveen建议的
$to = "naveen@gmail.com";
$subject = $name ." is contact ";
$headers = "MIME-Version: 1.0" . "'n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "'n";
@mail($to,$subject,$message,$headers);
将标头设置为mime版本&您的消息类型,如text/html/
要发送HTML内容/表格,您必须在邮件的标题中添加以下内容,
// To send HTML mail, the Content-type header must be set
$headers = 'MIME-Version: 1.0' . "'r'n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "'r'n";
mail($to, $subject, $message, $headers);
请参阅下面的链接,
邮件功能