安卓系统:Json无法从mysql数据库中检索任何文件——它是空的

我是android的新手，我使用的是mysql数据库，我在那里链接php文件进行连接，这很好，但我的代码没有显示任何内容，它只显示黑色背景，而不是显示数据库的数据

public class HomeFragment extends Fragment {

GridView gv;
@SuppressLint("NewApi")
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.home, container, false);
    StrictMode.enableDefaults();
    gv = (GridView) rootView.findViewById(R.id.gridView_home);
    getData();
    return rootView;
}
public void getData(){
    String result = "";
    InputStream isr = null;
    try{
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://192.168.1.2/Android/App/getcu.php"); //YOUR PHP SCRIPT ADDRESS 
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        isr = entity.getContent();
}
catch(Exception e){
        Log.e("log_tag", "Error in http connection "+e.toString());
        gv.setFilterText("Couldnt connect to database "+ e.getMessage()); //not printing anything
}
//convert response to string
try{
        BufferedReader reader = new BufferedReader(new InputStreamReader(isr,"iso-8859-1"),8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
                sb.append(line + "'n");
        }
        isr.close();
        result=sb.toString();
}
catch(Exception e){
        Log.e("log_tag", "Error  converting result "+e.toString());
}

try {

   String s = "";
   JSONArray jArray = new JSONArray(result);
   for(int i=0; i<jArray.length();i++){
       JSONObject json = jArray.getJSONObject(i);
       s = s + 
               "Name : "+json.getString("FirstName")+" "+json.getString("LastName")+"'n"+
               "Age : "+json.getInt("Age")+"'n"+
               "Mobile Using : "+json.getString("Mobile")+"'n'n";//+
               "Artist:"+json.put("Images",true ); // not printing anything 
   }
   gv.setFilterText(s); // not printing showing empty
} catch (Exception e) {

// TODO: handle exception
   Log.e("log_tag", "Error Parsing Data "+e.toString()); }
}  }

从文件夹Android/pictures/image1json检索图像时又出现一个错误，即没有打印部署到数据库中的特定图像

"Artist:"+json.put("Images",true ); 

使用json检索图像的上述语句正确吗？或者我必须更正

请帮助我更正上面的程序，感谢您宝贵的时间。我不明白为什么它没有打印任何东西，但当我将其扩展到活动时，它正在工作。如何在片段中使用它