我目前正在为一个练习做一些简单的计算器,但如果这里没有显示输出或结果,我的代码人员希望你能帮助我:/
<input type="radio" value= "Addition" name="calcu"> Addition .<br />
<input type="radio" value= "Subtraction" name="calcu"> Subtraction .<br />
<input type="radio" value= "Multiplication" name="calcu"> Multiplication .<br />
<input type="radio" value= "Division" name="calcu"> Division .<br />
<?php
$num1 = $_POST['num1'];
$num2 = $_POST['num2'];
$calcu = $_POST['calcu'];
function calculate($n1,$n2)
{
switch('$calcu')
{
case "Addition";
$compute = $n1 + $n2;
break;
case "Subtraction";
$compute = $n1 - $n2;
break;
case "Multiplication";
$compute = $n1 * $n2;
break;
case "Division";
$compute = $n1 / $n2;
break;
}
}
echo "$calcu <br /> <br /> 1st Number: $num1 <br /> 2nd Number: $num2 <br /><br />";
echo "Answer is:" .calculate($num1,$num2);
?>
以下是完整的代码:
<?php
$num1 = $_POST['num1'];
$num2 = $_POST['num2'];
$calcu = $_POST['calcu'];
function calculate($n1,$n2, $calcu) // set $calcu as parameter
{
switch($calcu)
{
case "Addition": // here you have to use colons not semi-colons
$compute = $n1 + $n2;
break;
case "Subtraction":
$compute = $n1 - $n2;
break;
case "Multiplication":
$compute = $n1 * $n2;
break;
case "Division":
$compute = $n1 / $n2;
break;
}
return $compute; // returning variable
}
echo "$calcu <br /> <br /> 1st Number: $num1 <br /> 2nd Number: $num2 <br /><br />";
echo "Answer is:" .calculate($num1,$num2, $calcu); // you need to pass $calcu as argument of that function
?>
将switch('$calcu')
更改为switch($calcu)
。应该是这样。
但不仅如此。您的变量是未定义的,因为您试图在提交表单之前对它们进行寻址,即它们还不存在。
$num1 = $_POST['num1'];
$num2 = $_POST['num2'];
$calcu = $_POST['calcu'];
你在那里称呼他们
echo "$calcu <br /> <br /> 1st Number: $num1 <br /> 2nd Number: $num2 <br /><br />";
echo "Answer is:" .calculate($num1,$num2);
实现这一点的正确方法是检查是否提交了表格:
<input type="radio" value= "Addition" name="calcu"> Addition .<br />
<input type="radio" value= "Subtraction" name="calcu"> Subtraction .<br />
<input type="radio" value= "Multiplication" name="calcu"> Multiplication .<br />
<input type="radio" value= "Division" name="calcu"> Division .<br />
<?php
if (isset($_POST)){
$num1 = $_POST['num1'];
$num2 = $_POST['num2'];
$calcu = $_POST['calcu'];
function calculate($n1,$n2)
{
switch('$calcu')
{
case "Addition";
$compute = $n1 + $n2;
break;
case "Subtraction";
$compute = $n1 - $n2;
break;
case "Multiplication";
$compute = $n1 * $n2;
break;
case "Division";
$compute = $n1 / $n2;
break;
}
}
echo "$calcu <br /> <br /> 1st Number: $num1 <br /> 2nd Number: $num2 <br /><br />";
echo "Answer is:" .calculate($num1,$num2);
unset($_POST);
}
?>
将switch('$calcu')
更改为switch($calcu)
。
正如@PeterM所提到的,您正在访问超出范围的变量$calcu
。要么将$calcu
变量传递给fun calculate
,要么通过$_POST
数组直接访问。
使用CCD_ 9。
或
function calculate($n1,$n2, $calcu) {
...
}
用calculate($n1,$n2, $calcu)
称之为乐趣。