夹具生成器代码 - Fixture generator code

Fixture generator code

本文关键字：代码夹具 | 更新日期: 2023-09-27

这是我的代码：

$totalRounds = 1;
$teams = array('Team 1', 'Team 2', 'Team 3', 'Team 4', 'Team 5');
echo 'Total Teams: ' , $totalTeams = count($teams) , '<br/>';
$turns = $totalTeams;
for($round=1; $round<$totalRounds+1; $round++){
    echo 'Round: ' , $round , '<br/>';
    for($homeTeam=0; $homeTeam<$totalTeams-1; $homeTeam++){
        for($awayTeam=0; $awayTeam<$totalTeams; $awayTeam++){
            if($teams[$homeTeam] != $teams[$awayTeam]){
                echo $teams[$homeTeam] , ' v/s ' , $teams[$awayTeam] , '<br/>';
            }                        
        }
        unset($teams[$homeTeam]);
    }
    echo '<br/>';
}

我的预期输出是：

Team 1 v/s Team 2 <br/>
Team 1 v/s Team 3 <br/>
Team 1 v/s Team 4 <br/>
Team 1 v/s Team 5 <br/>
Team 2 v/s Team 3 <br/>
Team 2 v/s Team 4 <br/>
Team 2 v/s Team 5 <br/>
Team 3 v/s Team 4 <br/>
Team 3 v/s Team 5 <br/>
Team 4 v/s Team 5 <br/>

我的实际输出是给我未定义的索引错误

一旦解决了这个问题，我不知道如何分配主客场球队。一队本应只有两场主场比赛，但却有四场。每支球队将进行2场主场比赛和2场客场比赛。

您的代码正在破坏数组，例如：

first iteration: $home = 0; $away = 0
end of iteration: delete teams[0]
second iteration, $home = 1; $away = 0 - OOPS, teams[0] no longer exists

与其在进行时取消设置数组，不如将内部循环建立在外部循环的基础上，例如：

for($home = 0; ...) {
   for($away = $home + 1; ...) {

您可以使用以下修复代码

$totalRounds = 1;
$teams = array('Team 1', 'Team 2', 'Team 3', 'Team 4', 'Team 5');
echo 'Total Teams: ' , $totalTeams = count($teams) , '<br/>';
$turns = $totalTeams;
for($round=1; $round<$totalRounds+1; $round++){
    echo 'Round: ' , $round , '<br/>';
    for($homeTeam = 0; $homeTeam < $totalTeams - 1; $homeTeam++) {
        for($awayTeam=$homeTeam + 1; $awayTeam < $totalTeams; $awayTeam++) {
            echo $teams[$homeTeam] , ' v/s ' , $teams[$awayTeam] , '<br/>';
        }
    }
    echo '<br/>';
}