我接受一个句子作为输入，如下所示：
abcd 01234 87 01235
接下来，我必须检查每个单词，看看它的字符在字母表中是否连续。输出如下：
abcd 01234
嗯，01235包含连续的字符，但整个单词也包含非连续的字符（35），所以它不会打印在屏幕上。
到目前为止，我写的是：
function string_to_ascii($string)
{
$ascii = NULL;
for ($i = 0; $i < strlen($string); $i++)
{
$ascii[] = ord($string[$i]);
}
return($ascii);
}
$input = "abcd 01234 87 01235";
//first, we split the sentence into separate words
$input = explode(" ",$input);
foreach($input as $original_word)
{
//we need it clear
unset($current_word);
//convert current word into array of ascii chars
$ascii_array = string_to_ascii($original_word);
//needed for counting how many chars are already processed
$i = 0;
//we also need to count the total number chars in array
$ascii_count = count($ascii_array);
//here we go, checking each character from array
foreach ($ascii_array as $char)
{
//if IT'S THE LAST WORD'S CHAR
if($i+1 == $ascii_count)
{
//IF THE WORD HAS JUST 1 char, output it
if($ascii_count == 1)
{
$current_word .= chr($char);
}
//IF THE WORDS HAS MORE THAN 1 CHAR
else
{
//IF PREVIOUS CHAR CODE IS (CURRENT_CHAR-1) (CONSECUTIVE, OUTPUT IT)
if(($char - 1) == $ascii_array[($i-1)])
{
$current_word .=chr($char);
}
}
}
//IF WE AREN'T YET AT THE ENDING
else
{
//IF NEXT CHAR CODE IS (CURRENT_CHAR+1) (CONSECUTIVE, OUTPUT IT)
if(($char + 1) == ($ascii_array[($i+1)]))
{
$current_word .=chr($char);
}
}
$i++;
}
//FINALLY, WE CHECK IF THE TOTAL NUMBER OF CONSECUTIVE CHARS is the same as THE NUMBER OF CHARS
if(strlen($current_word) == strlen($original_word))
{
$output[] = $current_word;
}
}
//FORMAT IT BACK AS SENTENCE
print(implode(' ',$output));
但也许还有另一种方法可以做到这一点，更简单？
抱歉拼写错误
这很有效。。。
$str = 'abcd 01234 87 01235';
$words = explode(' ', $str);
foreach($words as $key => $word) {
if ($word != implode(range($word[0], chr(ord($word[0]) + strlen($word) - 1)))) {
unset($words[$key]);
}
}
echo implode(' ', $words);
CodePad。
基本上，它获取每个单词的第一个字符，并创建字符范围，如果单词由连续字符组成，则字符范围将为值。
然后进行简单的字符串比较。
要获得更高性能的版本。。。
$str = 'abcd 01234 87 01235';
$words = explode(' ', $str);
foreach($words as $key => $word) {
foreach(str_split($word) as $index => $char) {
$thisOrd = ord($char);
if ($index > 0 AND $thisOrd !== $lastOrd + 1) {
unset($words[$key]);
break;
}
$lastOrd = $thisOrd;
}
}
echo implode(' ', $words);
CodePad。
这两个例子都依赖于字符的序数对于连续字符是连续的。ASCII就是这种情况，但我不确定其他字符。