如果数组元素在2个日期之间,则返回文本PHP


If array element is between 2 dates echo text PHP

我有以下PHP代码,我打算用它创建一封HTML电子邮件,它应该输出所有模型的详细信息,到期日在2个设定日期之间:

$sql = 'SELECT
GROUP_CONCAT(op.products_model),
GROUP_CONCAT(products.products_warranty_default),
GROUP_CONCAT(orders.date_purchased),
orders.customers_name
FROM orders_products op
INNER JOIN products
    ON op.products_id = products.products_id
INNER JOIN orders
    ON op.orders_id = orders.orders_id
INNER JOIN customers
    ON orders.customers_id = customers.customers_id
GROUP BY op.orders_id';
$result = mysql_query($sql, $connection);
while ($data = mysql_fetch_row($result)) {
    $models = explode(",",$data[0]); // create array from all models in the GROUP_CONCAT
    $years = explode(",",$data[1]); // create array from all years in the GROUP_CONCAT
    $dates = explode(",",$data[2]); // create array from all dates in the GROUP_CONCAT
    $name = $data[3];
    echo $header; // header of email (only the name changes on each loop)
    foreach ($models as $index => $model) {
    echo '
    <tr>
        <td width="149">
            <center>'.$model.'</center>
        </td>
        <td width="149">
            <center>'.date('d/m/Y', strtotime('+'.$years[$index].' years', strtotime($dates[$index]))).'</center>
        </td>
    </tr>'; // echos the model in first column and date+years in second column
    }
    echo $footer; // static HTML again like the header
}

我一直在思考的是,如果表中存在日期在两个日期之间的模型,即2014年5月1日至5月31日,如何仅输出页眉、表和页脚的组合。它当前正在输出所有日期。

我试过各种方法来做到这一点,但在大约6个小时的失败后,我准备把我的电脑扔出窗外。我只有几周的PHP经验(以及编程经验),所以它可能(希望)是一个我不知道的简单修复。

注意:我应该注意的是,对于我用来测试的当前数据库,我可以修改选择查询以输出相关日期,但在我使用的实际数据库(我只能在工作中访问该数据库)上没有保修字段,我必须通过php从产品的长描述中提取信息,并将其输入到一个函数中。

最终代码:

$sql = 'SELECT  op.products_model, 
        products.products_warranty_default,
        orders.date_purchased,
        orders.customers_name
   FROM orders_products op
  INNER JOIN products  ON op.products_id = products.products_id
  INNER JOIN orders    ON op.orders_id = orders.orders_id
  INNER JOIN customers ON orders.customers_id = customers.customers_id
  ORDER BY orders.customers_name, op.orders_id,
           op.products_model,
           products.products_warranty_default,
           orders.date_purchased';
$result = mysql_query($sql, $connection);
$previous_name = "";
while ($data = mysql_fetch_row($result)) {
    $model = $data[0];
    $year = $data[1];
    $date = $data[2];
    $name = $data[3];
    $expiry = strtotime('+'.$year.' years', strtotime($date));
    if ($previous_name != $name && $expiry >= strtotime('2014-05-01') && $expiry <= strtotime('2014-05-31')) {  // on a new customer name ...
        if ($previous_name != "") {
            // if there is a previous customer, write the footer
            echo $footer;
            $previous_name = $name; 
        }
    }
    if ($expiry >= strtotime('2014-05-01') && $expiry <= strtotime('2014-05-31')){
    echo '
    <tr>
        <td width="149">
                <center>'.$model.'</center>
        </td>
        <td width="149">
            <center>'.date('d/m/Y', $expiry).'</center>
        </td>
    </tr>'; // echos the model in first column and date+years in second column
    }
}
if ( $previous_name != "" && $expiry >= strtotime('2014-05-01') && $expiry <= strtotime('2014-05-31')) {
    echo $footer;
}

在SQL查询中聚合了很多东西,然后在PHP中对其进行分解,这似乎有点奇怪。我相信,这会让你很难匹配日期。

你可以尝试这个非聚合查询:

SELECT  op.products_model, 
        products.products_warranty_default,
        orders.date_purchased,
        orders.customers_name
   FROM orders_products op
  INNER JOIN products  ON op.products_id = products.products_id
  INNER JOIN orders    ON op.orders_id = orders.orders_id
  INNER JOIN customers ON orders.customers_id = customers.customers_id
  WHERE orders.date_purchased >= DATE('2014-05-01')
    AND orders.date_purchased <  DATE('2014-05-31') + INTERVAL 1 DAY
  ORDER BY orders.customer_name, op.orders_id,
           op.products_model,
           products.products_warranty_default,
           orders.date_purchased,

这将返回与日期范围匹配的详细记录。

我认为,用php处理结果集非常容易。您需要检测客户名称的更改才能输出页眉和页脚。这就是$previous_name的意义所在。

$previous_name = "";
while ($data = mysql_fetch_row($result)) {
    $model = $data[0];
    $year = $data[1];
    $date = $data[2];
    $name = $data[3];
    if ($previous_name != $name) {  /* on a new customer name ... */
        if ($previous_name != "") {
            /* if there is a previous customer, write the footer  */
            echo $footer; /* static HTML again like the header */
        }
        /* write the header for the new customer */
        echo $header; 
        /* pick up the new customer name */
        $previous_name = $name; 
    }
    echo '
    <tr>
        <td width="149">
            <center>'.$model.'</center>
        </td>
        <td width="149">
            <center>'.date('d/m/Y', strtotime('+'.$year.' years', 
                      strtotime($date))).'</center>
        </td>
    </tr>'; /* echos the model in first column and date+years in second column */
    }
} /* end while ($data... */
/* wrap up the report by writing the final footer if need be */
if ( $previous_name != "" ) {
    echo $footer; /* static HTML again like the header */
}    

看看进展如何?您从SQL中请求一个详细的结果集,然后使用PHP中的一些编程技术按客户划分结果集。

这比获得一个GROUPed结果集然后尝试取消分组更容易、更可靠。

在foreach循环中,只需执行if语句来检查$row数据是否在您的日期范围内,如果是,则执行回显,否则不执行任何操作。

例如:

foreach ($models as $index => $model) {
    if ($years[$index] >=  DATE('2014-05-01') && $years[$index] <=  DATE('2014-05-31')){
        echo '
        <tr>
            <td width="149">
               <center>'.$model.'</center>
           </td>
           <td width="149">
               <center>'.date('d/m/Y', strtotime('+'.$years[$index].' years', strtotime($dates[$index]))).'</center>
           </td>
           </tr>';
    }
}