我有一个很久以前的脚本，它以eg: 1 Min 的形式将unix戳更改为大约时间
我的脚本（PHP）：
<?php
$periods = array("sec", "min", "hr", "day", "week", "month", "yr");
$lengths = array("60","60","24","7","4.35","12","10");
$span = time() - $row['post_time'];
$tense = "ago";
for($j = 0; $span >= $lengths[$j] && $j < count($lengths)-1; $j++)
{
$span /= $lengths[$j];
}
$span = round($span);
if($span != 1) {
$periods[$j].= "s";
}
$time_elapse = $span.' '.$periods[$j] ; //will output in the form of 1min or 1hr
?>
我的问题：我如何修改此脚本以显示unix时间戳，该时间戳将导致和大约超过2年的时间转换为dd-mm-yyyy格式的
为那些不了解的人解释
测试代码/脚本
<?php
$initial_time="946681200";//the unix timestamp is for Jan 1 2001
$periods = array("sec", "min", "hr", "day", "week", "month", "yr");
$lengths = array("60","60","24","7","4.35","12","10");
$span = time() - $initial_time;
$tense = "ago";
for($j = 0; $span >= $lengths[$j] && $j < count($lengths)-1; $j++)
{
$span /= $lengths[$j];
}
$span = round($span);
if($span != 1) {
$periods[$j].= "s";
}
$time_elapse = $span.' '.$periods[$j] ;
?>
上面的代码将unix时间戳"946681200"转换为近似时间，即14yrs，但我希望以DD-MM-YYYY格式
这些代码所做的就是创建两个DateTime对象：一个表示两年前，一个表示初始化时间。然后对它们进行比较（DateTime对象是可比较的）。如果$initial_date大于两年前，它只会按照您要求的格式将该日期分配给$time_elapse。否则，您的代码将照常运行。
<?php
$initial_time="946681200";//the unix timestamp is for Dec 31, 1999
$two_years_ago = new DateTime('-2 years');
$initial_date = new DateTime('@' . $initial_time);
if ($initial_date < $two_years_ago) {
$time_elapse = $initial_date->format('d-m-Y');
}
else {
$periods = array("sec", "min", "hr", "day", "week", "month", "yr");
$lengths = array("60","60","24","7","4.35","12","10");
$span = time() - $initial_time;
$tense = "ago";
for($j = 0; $span >= $lengths[$j] && $j < count($lengths)-1; $j++)
{
$span /= $lengths[$j];
}
$span = round($span);
if($span != 1) {
$periods[$j].= "s";
}
$time_elapse = $span.' '.$periods[$j] ;
}
?>
演示