MySQL;PHP:一次查询3行


MySQL & PHP: querying 3 rows at a time

我正在使用数据库创建照片库。在每行上,在一切重置之前显示3个图像。它将采用<img>/<img>/<img>/<div>格式。

因此,当你查看源代码时,你会发现:

<img src="1" alt="">
<img src="2" alt="">
<img src="3" alt="">
<div class="clear-both"></div>

它会对数据库中的每一行不断重复这一点。所以9个图像将是:

<img src="1" alt="">
<img src="2" alt="">
<img src="3" alt="">
<div class="clear-both"></div>
<img src="4" alt="">
<img src="5" alt="">
<img src="6" alt="">
<div class="clear-both"></div>
<img src="7" alt="">
<img src="8" alt="">
<img src="9" alt="">
<div class="clear-both"></div>

我想我可以用while来处理这个问题。但我不知道该添加什么SQL或PHP语句。我曾想过使用WHEREGROUP BYCOUNT,但这些都不起作用。

如果可能的话,我还希望它能够处理只有1和2个图像的行。这意味着如果表中有4行,那么它将显示:

<img src="1" alt="">
<img src="2" alt="">
<img src="3" alt="">
<div class="clear-both"></div>
<img src="4" alt="">
<div class="clear-both"></div>

如果有8个,那么它会显示:

<img src="1" alt="">
<img src="2" alt="">
<img src="3" alt="">
<div class="clear-both"></div>
<img src="4" alt="">
<img src="5" alt="">
<img src="6" alt="">
<div class="clear-both"></div>
<img src="7" alt="">
<img src="8" alt="">
<div class="clear-both"></div>

谢谢你的帮助。

PHP

$Database4 = new mysqli("localhost", "user", "pass", "Photography");
$Photos = $Database4 -> query("SELECT *
                               FROM `Year2016`
                               -- ORDER BY DateTaken
                               ;");
while ($DataRows = $Photos -> fetch_array()) {
 echo '<img src="photography/small/' . $DataRows["file"] . '" alt="">' . "'n";
}
echo '<div class="clear-both"></div>' . "'n";

SQL

CREATE TABLE `Year2016`(
 `file` text COLLATE utf8_bin NOT NULL,
)
ENGINE = InnoDB
DEFAULT CHARSET = utf8
COLLATE = utf8_bin;
INSERT INTO `Year2016`(`file`)
VALUES
('red-1.png'),
('red-2.png'),
('red-3.png'),
('red-4.png'),
('red-5.png'),
('red-6.png');

这很简单:

$i = 1;    // special counter
while ($DataRows = $Photos -> fetch_array()) {
    echo '<img src="photography/small/' . $DataRows["file"] . '" alt="">' . "'n";
    if ($i % 3 == 0) {
        echo '<div class="clear-both"></div>';
    }
    $i++;
}
// the last one if last `$i` value is not divided by 3
if ($i % 3 != 1) {
    echo '<div class="clear-both"></div>';
}