$this->db->select("*");
$this->db->from("panTab");
$this->db->where("QCJobPanelTestId = ",$TestId);
$query = $this->db->get();
$data['get_JobPan_Data'] = $query->result();
for($i = 0; $i < sizeof($data['get_JobPan_Data']);$i++)
{
$table = "Form1";
$whereField1 = "QC1TestId";
$whereField2 = "QC1JobPanelId";
$currDiv = "form1";
$this->db->select("*");
$this->db->from($table);
$this->db->where($whereField1." = ",$TestId);
$this->db->where($whereField2." = ",$data['get_JobPan_Data'][$i]['QCJobPanelId']); //--This value gives an error . How to access it?
$query1 = $this->db->get();
$data['getTestData'] = $query1->result();
}
即将到来的数据
Array (
[get_JobPan_Data] => Array (
[0] => stdClass Object(
[QCJobPanelId] => 293 [QCJobPanelNo] => 1
[QCJobPanelDesc] => Pan 1
[QCJobPanelJobId] => 3
[QCJobPanelPanelId] => 0
[QCJobPanelTestId] => 63
)
[getTestData] => Array (
[0] => stdClass Object (
[QC1Id] => 77
[QC1JobId] => 3
[QC1TestId] => 63
[QCTestDesc] => 0
[QC1DielectricACC_LC] => 0
[QC1DielectricACC_IRA] => 0
[QCRemark] => Completed
[QCTestedBy] => aa
[QCReviewedBy] => bb
[QCWitnessedBy] => cc
[QC1JobPanelId] => 293
[QCTestCompletionDate] => 2016-07-29 00:00:00
[QC1DateAdded] => 2016-07-29
)
)
)
也无法从$data['getTestData']
获取值:
尝试使用:
$data['getTestData'][0]['TestDesc']
$data['getTestData'][0][0]['TestDesc']
$data['getTestData']['TestDesc']
访问$data的答案,包括@Anish&Anant:
- $data['getTestData'][0]->TestDesc
- ResultVariable[Array1][Array2]->对象变量
简而言之:-如果是Array,则使用[]
-如果是Object,则使用->
是的,访问对象有错误
$this->db->where($whereField2." = ",$data['get_JobPan_Data'][$i]['QCJobPanelId']);
用代替
$this->db->where($whereField2." = ",$data['get_JobPan_Data'][$i]->QCJobPanelId);