代码
看第二个做下面的第二个回波
do {
echo "<strong>Topic:". $row_AllTopics['topic'] . "</strong><br>";
mysql_select_db($database_Select, $Select);
$query_Comments = sprintf("SELECT * FROM comments where ((event_id=%s) AND (topic_id=%s)) ", $_POST['event_id'], $row_AllTopics['id']);
$Comments = mysql_query($query_Comments, $Select) or die(mysql_error());
$row_Comments = mysql_fetch_assoc($Comments);
$totalRows_Comments = mysql_num_rows($Comments);
do {
// This is the echo in question.
echo $row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "'n";
} while ($row_Comments = mysql_fetch_assoc($Comments));
} while ($row_AllTopics = mysql_fetch_assoc($AllTopics));
输出
(此文本在屏幕上居中对齐(
Topic:computer
linuxPosted by: andy linuxPosted by: andy Topic:computer
Posted by: Topic:ji
poPosted by: andy Topic:drive
makPosted by: andy Topic:new
nicePosted by: andy Topic:golf
holePosted by: andy plPosted by: andy
请尝试使用<br>而不是'n。
您可以通过以下方式在PHP中使用nl2br((函数：
echo nl2br($row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "'n");
这将把'n转换为<br/>。
"'n"将导致源代码中的换行。当你的浏览器将呈现html时，你需要使用html换行符(<br>或<br />(，这将给出预期的结果。
所以，你的代码将是这样的：
之前：echo $row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "'n";
之后：echo $row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "<br />";