在Yii中，您可以以JSON而不是HTML/XML返回HTTP错误响应 - In Yii can you return an HTTP error response in JSON instead of HTML/XML?

In Yii can you return an HTTP error response in JSON instead of HTML/XML?

如果用户试图在没有适当凭证的情况下访问REST api，我的yii应用程序会在controller.php文件中抛出401错误，如下所示:

throw new UnauthorizedHttpException('Access unavailable without access_token.', 401);

返回如下格式的错误:

<?xml version="1.0" encoding="UTF-8"?>
<response>
  <name>Unauthorized</name><message>Access unavailable.</message>      
  <code>401</code>
  <status>401</status>
  <type>yii'web'UnauthorizedHttpException</type>
</response>

如何以JSON格式返回此错误?

{
    "name": "Access unavailable.",
    "message": "You are not authorized.",
    "code": 0,
    "status": 401
}

我的移动应用程序访问这个资源需要一个JSON对象

尝试在您的自定义__construct中返回或更好的上面添加这个。

Yii::$app->response->format = 'json';

yii2 rest控制器对"Accept" HTTP报头作出反应。如果在这个报头中只有"application/json"存在，那么rest控制器的答案将是json

这对我来说很有效。扩展activeController，我把它放在api'controllers'ActiveController.php

namespace api'controllers;
class ActiveController extends yii'rest'ActiveController {
    public function behaviors() {
        $behaviors = parent::behaviors();
        $behaviors['contentNegotiator'] = [
            'class' => 'yii'filters'ContentNegotiator',
            'formats' => [
                'application/json' => 'yii'web'Response::FORMAT_JSON,
            ]
        ];
        return $behaviors;
    }
}

then in my controller

use api'controllers'ActiveController;
class blablaController extends ActiveController
{
...
}

现在在未经授权的情况下，我得到一个JSON而不是XML

{"success":false,"data":{"name":"Unauthorized","message":"Your request was made with invalid credentials.","code":0,"status":401}}