我想就我的会话问题寻求帮助。:)有一个活跃的会话,我使用的大部分页面是$_SESSION['result'] = $result;
然后,当这个是活动的,我试图传递另一个会话,但它仍然检索上述会话。
一切从这里开始
<?php
session_start();
$loginuser = $_SESSION['result'];
?>
<div>
<p class="editedp"><a href="timekeepingquery.php">Time Keeping Logs</a></p>
</div>
这是我试图通过的会话,而另一个会话仍在活动
timekeepingquery.php
<?php
$con=mysqli_connect("localhost","root","","leavecalendar");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = mysqli_query($con,"SELECT * FROM timekeeping ");
while($row = mysqli_fetch_array($sql))
if(!empty($row)){
$_SESSION['line'] = $row;
header("location:timekeepinglogs.php");
}
?>
下面是我如何检索上面所述的会话。
timekeepinglogs.php
<?php
session_start();
$dataline = $_SESSION['line']; <-------this is where it says error
?>
这是我得到的错误
Undefined index: line in C:'xampp'htdocs'final'timekeepinglogs.php on line 3
欢迎回答。
您忘记在timekeepingquery.php顶部放置session_start();