如何使php代码生成这个json - How to made php code to generate this json?

How to made php code to generate this json?

本文关键字：json 代码生成何使 php | 更新日期: 2023-09-27

这是mysql查询的结果

` date      |    link                               |sum
2015-06-29  |uploads/1_29_06_2015_9_18_37_image.jpg |6
2015-06-29  |uploads/1_29_06_2015_13_57_54_image.jpg|2
2015-06-30  |uploads/1_30_06_2015_0_26_44_image.jpg |2
2015-07-01  |uploads/1_01_07_2015_2_44_47_image.jpg |3
2015-07-01  |uploads/1_01_07_2015_5_15_47_image.jpg |4
2015-07-02  |uploads/1_02_07_2015_1_40_05_image.jpg |2`

谁能帮我生成一个json与以下格式通过PHP。

[
{ 
"date": "2015-06-29",
"values": [{"image":"uploads/1_29_06_2015_9_18_37_image.jpg","sum":6},{"image":"uploads/1_29_06_2015_13_57_54_image.jpg","sum":2}]
},
{ 
"date": "2015-06-30 ",
"values": [{"link":"uploads/1_30_06_2015_0_26_44_image.jpg","sum":2}]
}
]

当链接和求和在同一天时，我想将它们分组在一起。

更新1:

这是我的代码:

<?php

$uid = $_SESSION['uid']; 
  $registerquery = mysql_query("select DATE(date) as dates,pic, sum(veg)+sum(fruit) as sum from diary where u_id = $uid and  pic !='' group by date;");


$data = array();
foreach (mysql_fetch_row($registerquery) as $row) {
  if (!array_key_exists($row['dates'], $data)) {
    $data[$row['dates']] = array('date' => $row['dates'], 'values' => array());
  }
  $data[$row['dates']]['values'][] = array(
    'image' => $row['pic'],
    'sum' => $row['sum']      
  ); 
}
//this is your JSON
echo json_encode(array_values($data));
?>

但是我似乎只得到了第一个字符。

[{"date":"2","values":[{"image":"0","sum":"1"}]},{"date":"u","values":[{"image":"p","sum":"l"}]},{"date":"6","values":[{"image":"","sum":""}]}]

假设$rows包含所有获取的行:

$data = array();
foreach ($rows as $row) {
  if (!array_key_exists($row['DATE'], $data)) {
    $data[$row['DATE']] = array('date' => $row['DATE'], 'values' => array());
  }
  $data[$row['DATE']]['values'][] = array(
    'image' => $row['LINK'],
    'sum' => $row['SUM']      
  ); 
}
//this is your JSON
echo json_encode(array_values($data));

<?php include "connect.php"; ?>
<?php

$uid = $_SESSION['uid']; 
  $registerquery = mysql_query("select DATE(date) as dates,pic, sum(veg)+sum(fruit) as sum from diary where u_id = $uid and  pic !='' group by date;");


$data = array();
while($row =  mysql_fetch_array($registerquery)) {
//    echo $row['dates']; echo "   "; echo $row['pic'];  echo "  ";  echo $row['sum']; echo "<br><br>";
    if (!array_key_exists($row['dates'], $data)) {
    $data[$row['dates']] = array('date' => $row['dates'], 'values' => array());
  }
    $data[$row['dates']]['values'][] = array(
    'image' => $row['pic'],
    'sum' => $row['sum']      
  ); 
}
echo json_encode(array_values($data));

?>