PHP while循环输出为每个项目生成select - php while loop output producing select for each item

我知道我的编码不正确，但似乎无法找到纠正它的方法。其目的是有一个下拉菜单显示填充的结果从mysql数据库。它目前为每个地址显示一个下拉列表。我知道为什么会发生这种情况，但似乎无法纠正它。应该把echo从while循环中取出来吗?或者位置是正确的，但在其他地方是错误的?如果有人能检查一下并告诉我哪里出了问题，我将不胜感激。多谢。

<?php
    $customer = mysql_real_escape_string( $_GET["customer"] );         
    $con = mysql_connect("localhost","root","");
    $db = "sample";
      if (!$con)
        {
        die('Could not connect: ' . mysql_error());
        }
        mysql_select_db($db, $con);
        $query_rs_select_address2 = sprintf("SELECT * FROM company_com where idcode_com = '$customer'");
        $rs_select_address2 = mysql_query($query_rs_select_address2, $con) or die(mysql_error());
        $row_rs_select_address2 = mysql_fetch_assoc($rs_select_address2);
        $totalRows_rs_select_address2 = mysql_num_rows($rs_select_address2);
        while ($row_rs_select_address2 = mysql_fetch_assoc($rs_select_address2))
            {  
        $address=$row_rs_select_address2['address1_com']. " ". $row_rs_select_address2['address2_com']. " ". $row_rs_select_address2['address3_com']. " ". $row_rs_select_address2['town_com']. " ". $row_rs_select_address2['postcode_com'];
        echo '<select name="customer">'.'<option value="">Select delivery address</option>'.'<option value="address">'.$address.'</option>'.'</select>';
            }
?>

如果您的目标是让一个下拉菜单包含所有选项，那么您需要将select 的打开和关闭标记的echo放置在while的之外，并将选项标记留在while的中:

// also put first option on the outside as you *don't* want to repeat that.
echo '<select name="customer"><option value="">Select delivery address</option>';
while ($row_rs_select_address2 = mysql_fetch_assoc($rs_select_address2))
{  
    // only place the code in here you want repeated for every value in the query
    /* 
        have you considered concatenating in the query?
        Basically:
        select concat( address1_com, ' ', address2_com, ' ', address3_com, ' '
               town_com, ' ', postcode_com ) as full_address From...
        Sometimes the greater number of records means slower execution.
        Of course, you should benchmark to be sure.
    */
    $address=  $row_rs_select_address2['address1_com']. " ". 
               $row_rs_select_address2['address2_com']. " ". 
               $row_rs_select_address2['address3_com']. " ". 
               $row_rs_select_address2['town_com']. " ". 
               $row_rs_select_address2['postcode_com'];
    // notice I swapped out $uid for address. You want to have each option 
    // reflect a different value so that the POST gives a uid to the server
    // You can probably get a uid from the primary key of the company_com 
    // table.
    echo '<option value="$uid">'.$address.'</option>';
}
echo '</select>';

试试这个:

echo '<select name="customer">';
echo '<option value="">Select delivery address</option>';
while ($row_rs_select_address2 = mysql_fetch_assoc($rs_select_address2))
{  
    $address=$row_rs_select_address2['address1_com']. " ". $row_rs_select_address2['address2_com']. " ". $row_rs_select_address2['address3_com']. " ". $row_rs_select_address2['town_com']. " ". $row_rs_select_address2['postcode_com'];
    echo '<option value="address">'.$address.'</option>';
}
echo '</select>';

while循环每次产生一个select元素。

你应该把select放在while

之外

echo "<select>";
while(/* while statement */){
    echo "<option></option>";
}
echo "</select>";

将while改为this

echo '<select name="customer">';
echo '<option value="">Select delivery address</option>';
while ($row_rs_select_address2 = mysql_fetch_assoc($rs_select_address2))
{          
     $address=$row_rs_select_address2['address1_com']. " ". $row_rs_select_address2['address2_com']. " ". $row_rs_select_address2['address3_com']. " ". $row_rs_select_address2['town_com']. " ". $row_rs_select_address2['postcode_com'];       
     echo '<option value="address">'.$address.'</option>'
}
echo '</select>';

试试这样:

echo '<select name="customer">';
while ($row_rs_select_address2 = mysql_fetch_assoc($rs_select_address2))
            {  
        $address=$row_rs_select_address2['address1_com']. " ". $row_rs_select_address2['address2_com']. " ". $row_rs_select_address2['address3_com']. " ". $row_rs_select_address2['town_com']. " ". $row_rs_select_address2['postcode_com'];
        echo '<option value="">Select delivery address</option>'.'<option value="address">'.$address.'</option>';
            }
echo '</select>';

您正在为每(表中的行)制作不同的内容，希望这对您有所帮助:)。