如何从DOMXPath查询中获得特定的值


How do I get specific values from a DOMXPath query?

我是DOMXPath的新手,但我正在努力学习更多。目前我有一个这样的HTML结构:

    <span class="1">
        <div class="headerClass">
            Here you have <span class="spanClass1">some text</span>. And here there is <span class="spanClass2">even more text</span>
        </div>
        <table class="tableClass" id="tableID">
            <tr>
                <td>some text</td>
                <td>some text</td>
                <td>some text</td>
            </tr>
            <tr>
                <td>some text</td>
                <td>some text</td>
                <td><a href="http://www.website1.com" target="_blank">My Link</a></td>
            </tr>
            <tr>
                <td>some text</td>
                <td>some text</td>
                <td><a href="http://www.website2.com" target="_blank">My Link</a></td>
            </tr>
        </table>
    </span>
    <span class="2">
        <div class="headerClass">
            Here you have <span class="spanClass1">some text</span>. And here there is <span class="spanClass2">even more text</span>
        </div>
        <table class="tableClass" id="tableID">
            <tr>
                <td>some text</td>
                <td>some text</td>
                <td>some text</td>
            </tr>
            <tr>
                <td>some text</td>
                <td>some text</td>
                <td><a href="http://www.website1.com" target="_blank">My Link</a></td>
            </tr>
            <tr>
                <td>some text</td>
                <td>some text</td>
                <td><a href="http://www.website2.com" target="_blank">My Link</a></td>
            </tr>
        </table>
    </span>
... and the spans continue: 3, 4, 5 ... etc
为了从源文件中检索HTML代码,我使用如下命令:
$oDomXpath = new DOMXpath($oDom);
$query = "//span[number(@class)=number(@class)]";   
$oDomObject = $oDomXpath->query($query);
foreach ($oDomObject as $oObject) {
    // WHAT GOES HERE????
}

我需要在数组中存储以下值:

  1. 所有<div class="headerClass">的纯文本,不含html标签。
  2. 所有<span class="spanClass2">的文本
  3. 所有的url都在表中。表可以有从0到多的任意行数。

我怎样才能做到这一点?我需要在foreach循环中放入什么?我是否需要运行另一个查询??

提前感谢您的帮助!

您可以选择,您可以使用几个XPath查询并逐个获取值,或者您可以使用几个路径构建一个唯一的XPath查询:

<pre><?php
$dom = new DOMDocument();
@$dom->loadHTMLFile('yourfile.html');
$xpath = new DOMXPath($dom);
$xquery = <<<'EOD'
//span[number(@class)=@class]/@class |
//span[number(@class)=@class]/div[@class='headerClass'] |
//span[number(@class)=@class]/div[@class='headerClass']/span[@class='spanClass2'] | 
//span[number(@class)=@class]/table[@class='tableClass']/tr/td/a
EOD;
$nodes = $xpath->query($xquery);
foreach ($nodes as $node) {
    if ($node->nodeType == XML_ELEMENT_NODE)
        switch($node->nodeName):
            case 'div' : echo '<br/>div content: ' . $node->nodeValue; break;
            case 'span': echo '<br/>span content: ' . $node->nodeValue; break;
            default    : echo '<br/>url: ' . $node->getAttribute('href');
        endswitch;
    else
        echo '<br/><br/>number: ' . $node->value;
}