这是我的php文件,我想同时在两行中插入状态值。
<?php
include_once 'db_connect.php';
if(isset($_POST['btn-signup']))
{
$PersonID = mysql_real_escape_string($_POST['PersonID']);
$FirstName = mysql_real_escape_string($_POST['FirstName']);
$Status = mysql_real_escape_string($_POST['Status']);
$uname = trim($uname);
$email = trim($email);
$upass = trim($upass);
// email exist or not
$query = "SELECT PersonID FROM attandance WHERE PersonID='$PersonID'";
$result = mysql_query($query);
$count = mysql_num_rows($result); // if email not found then register
if($count == 0){
if(mysql_query("INSERT INTO state(PersonID,FirstName,Status) VALUES('$PersonID','$FirstName','$Status')"))
{ ?>
<script>alert('successfully Added ');</script>
<?php
}
else
{ ?>
<script>alert('error while registering you...');</script>
<?php
}
}
else
{
?>
<script>alert('Sorry PersonID already taken ...');</script>
<?php
}
}
echo "<!DOCTYPE html>'n";
echo "<html>'n";
echo "<head>'n";
echo " <meta charset='"utf-8'">'n";
echo " <meta http-equiv='"X-UA-Compatible'" content='"IE=edge'">'n";
echo " <title>AdminLTE 2 | Blank Page</title>'n";
echo "</head>'n";
echo "<body>'n";
echo " 'n";
echo "'n";
echo "'n";
include_once 'dbconnect.php';
$query = "SELECT * FROM attandance ";
$result = mysql_query($query);
echo "<table border='"2'">'n";
echo " <tr>'n";
echo " <th>PersonId</th>'n";
echo " <th>First Name</th>'n";
echo " <th>Status</th>'n";
echo " </tr>'n";
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
$PersonID=$row['PersonID'];
$FirstName=$row['FirstName'];
echo "<td> <input type='"text'" name='"user_id'" value='" $PersonID'"> </td>'n";
echo "<td> <input type='"text'" name='"full_name'" value='" $FirstName'"></td>'n";
echo "<td> <input type='"text'" name='"full_name'" value='" $Status'"></td>'n";
echo "</tr>'n";
}
echo " </table>'n";
echo "<input id='"button'" type='"submit'" name='"btn-signup'" value='"Sign-Up'">'n";
echo "</body>'n";
echo "</html>'n";
echo "'n";
?>
我想使用按钮一次添加两个字段的状态。但这并没有奏效。有人能帮我吗?在状态表中,我想同时向两行添加值。
不良代码:)但是
你读这篇文章
$PersonID = mysql_real_escape_string($_POST['PersonID']);
$FirstName = mysql_real_escape_string($_POST['FirstName']);
$Status = mysql_real_escape_string($_POST['Status']);
和这个输入
echo "<td> <input type='"text'" name='"user_id'" value='" $PersonID'"> </td>'n";
echo "<td> <input type='"text'" name='"full_name'" value='" $FirstName'"></td>'n";
echo "<td> <input type='"text'" name='"full_name'" value='" $Status'"></td>'n";
更改输入的名称,试试这个
echo "<td> <input type='"text'" name='"PersonID'" value='" $PersonID'"> </td>'n";
echo "<td> <input type='"text'" name='"FirstName'" value='" $FirstName'"></td>'n";
echo "<td> <input type='"text'" name='"Status'" value='" $Status'"></td>'n";
, form在哪里?请阅读:http://php.net/manual/en/tutorial.forms.php