我有一个表单，允许人们输入不同长度的时间，例如:
input.time1 = "19:00"
input.time2 = "2:30"
input.time3 = "0:30"
我需要将这3次加在一起，然后从我拥有的基础值(21:00)中减去它。
$base = "21:00"
然后我需要这样写:
$total = $time1 + $time2 + $time3; //equals 22:00
$base = "21:00"; // set value
$diff = $base - $total; // 21:00 - 22:00 = -1:00(mm:ss)
希望这些都是有意义的，如果我需要更详细地解释什么，请让我知道。谢谢你！
你应该做
<?php
$time = "19:00";
$time2 = "2:30";
$time3 = "0:30";
$secs = strtotime($time2)-strtotime("00:00");
$secs1 = strtotime($time3)-strtotime("00:00");
$result = date("H:i",strtotime($time)+$secs+$secs1);
echo $result;
现在$result将具有附加值
从附加值
中减去另一个值$base = "21:00";
$TimeStart = strtotime($result);
$TimeEnd = strtotime($base);
$Difference = ($TimeEnd - $TimeStart);
echo gmdate("H:i", $Difference);
$base = strtotime('21:00'); $total = strtotime($time1)+strtotime($time2);+strtotime($time3) $diff = date("H:i", strtotime("$total - $base"));
快速和肮脏的例子自己动手的方法:
function string_to_int($time) {
list($minutes, $seconds) = explode(':', $time);
return $minutes * 60 + $seconds;
}
function int_to_string($seconds) {
return sprintf('%d:%02d', floor($seconds / 60), $seconds % 60);
}
$duration = string_to_int('19:00') + string_to_int('2:30') + string_to_int('0:30');
echo int_to_string($duration);
将xx:yy转换为整秒的整数，将它们相加，然后将其格式化为xx:yy以供人类可读输出。