我正在尝试连接到我的在线数据库与android。在遵循教程之后,我想出了这段代码:
package com.example.helloandroid;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.*;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
public class HelloAndroid extends Activity {
JSONArray jArray;
String result = null;
InputStream is = null;
StringBuilder sb=null;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://192.168.1.4/~jasptack/Software%20engineering/connector.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "'n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "'n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","x-co: "+json_data.getInt("x-coordinaat")+
", straat: "+json_data.getString("straat")
);
}
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
}
}
当我执行这个,我得到以下错误:[12-04] 23:25:07.711: E/log_tag(353): Error parsing data org.json.JSONException: Value . Error
有人能帮忙吗?谢谢!
如果JSON字符串格式错误,就会发生这种情况。确保String
result
是有效的JSONArray
(应该以'['开头)。另外,您可以尝试将result
映射到JSONObject
。如果这些都很好,JSONArray
内部的一个元素是畸形的。
我曾经尝试解析我的web服务返回的JSON字符串。以下是我所做的:
我从web服务得到的响应是:{"checkrecord":[{"rollno":"abc2"、"比例":40岁的"出席":12,"错过":34}],"表1":[]}
为了解析,我做了以下操作:
JSONObject jsonobject = new JSONObject(result);
JSONArray array = jsonobject.getJSONArray("checkrecord");
int max = array.length();
for (int j = 0; j < max; j++)
{
JSONObject obj = array.getJSONObject(j);
JSONArray names = obj.names();
for (int k = 0; k < names.length(); k++)
{
String name = names.getString(k);
String value= obj.getString(name);
}
我的JSONObject是这样的:
{"表1":[],"checkrecord":[{"错过":34岁"出席":12,"比例":40岁的"rollno":"abc2"}]}
这就是@500865想要暗示的。我刚给了你一个代码样本。先检查你的结果,确定它是否有效。还要检查JSONArray结果。如果可能的话,把它贴在这里。
希望有帮助
欢呼