Php -添加到数组失败，添加引用

我的php环境有一些奇怪的问题:

public static function getAllVotesOfGroup($groupid){
    $con = new 'SYSTEM'DB'Connection(new 'DBD'uVote());
    $res = $con->prepare(   'selVoteByGrp',
                            'SELECT * FROM `uvote_votes` WHERE `group` = ?;',
                            array($groupid));
    $result = array();
    //$r = array();
    while($r = $res->next()){                        
        //print_r($r);                        
        $result[] = $r;
        print_r($result);            
        echo "</br></br>";
    }           
    //print_r($result);
    return $result;
}

public function next($object = false, $result_type = MYSQL_BOTH){        
    if($object){
        $this->current = mysqli_fetch_object($this->res);
    } else {
        $this->current = mysqli_fetch_assoc($this->res);
    }
    return $this->current;
}

在我的另一台机器上，这段代码返回我想要的所有值，这台机器返回这个:->从getAllVotesOfGroup(1)的回声代码

Array ( [0] => Array ( [ID] => 1 [group] => 1 [title] => Test [text] => Testabstimmung [time_start] => 2013-06-12 [time_end] => 2015-06-13 ) ) 
Array ( [0] => Array ( [ID] => 2 [group] => 1 [title] => Test2 [text] => Testabstimmung [time_start] => 2014-06-13 [time_end] => 2012-06-16 ) [1] => Array ( [ID] => 2 [group] => 1 [title] => Test2 [text] => Testabstimmung [time_start] => 2014-06-13 [time_end] => 2012-06-16 ) ) 
Array ( [0] => Array ( [ID] => 3 [group] => 1 [title] => Test3 [text] => bla [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) [1] => Array ( [ID] => 3 [group] => 1 [title] => Test3 [text] => bla [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) [2] => Array ( [ID] => 3 [group] => 1 [title] => Test3 [text] => bla [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) ) 
Array ( [0] => Array ( [ID] => 4 [group] => 1 [title] => Test4 [text] => blub [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) [1] => Array ( [ID] => 4 [group] => 1 [title] => Test4 [text] => blub [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) [2] => Array ( [ID] => 4 [group] => 1 [title] => Test4 [text] => blub [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) [3] => Array ( [ID] => 4 [group] => 1 [title] => Test4 [text] => blub [time_start] => 0000-00-00 [time_end] => 0000-00-00 ) ) 

可以看到前面的值被替换了，可能是因为$r是一个引用，并且只有引用被添加到数组中，而不是实际的值。

为什么?我可以设置一些php.ini选项来改变这种行为吗?

添加:这工作得很好!但这不是我想要的;-)

    $result = array();
    while($r = $res->next()){                        
        $result[] = array('title' => $r['title'],'text' => $r['text']);
    }           
    return $result;

好的，我可以解出来;-)

见http://www.php.net/manual/en/mysqli-stmt.fetch.php # 83284

问题是我使用的mysqlli -stmt-fetch将返回一个引用而不是数据。