我正在尝试使用json将数据发布到我的php文件。在我的php文件中，我想使用mySQL-Select-Statement的发布数据，并将选择返回给我的代码，并将其显示为列表。
最简单的方法是什么?
这是我的'postData()': public void postData() {
//trying
List<Map<String, String>> buyCategories = new ArrayList<Map<String, String>>();
//trying
try{
// url where the data will be posted
String postReceiverUrl = "http://www.url.de/getArticles.php";
// HttpClient
HttpClient httpClient = new DefaultHttpClient();
// post header
HttpPost httpPost = new HttpPost(postReceiverUrl);
int cat = UsingSharedPrefs.getChosenCategorie();
if(cat == 0) {
cat = 100;
}
String cats = Integer.toString(cat);
// add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("categorieId", cats));
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// execute HTTP post request
HttpResponse response = httpClient.execute(httpPost);
HttpEntity resEntity = response.getEntity();
if (resEntity != null) {
JSONObject jsonResponse = new JSONObject(jsonResult);
JSONArray jsonMainNode = jsonResponse.getJSONArray("testproducts");
for (int i = 0; i < jsonMainNode.length(); i++) {
JSONObject jsonChildNode = jsonMainNode.getJSONObject(i);
String name = jsonChildNode.getString("testproduct_name");
String price = jsonChildNode.getString("testproduct_price");
String path = jsonChildNode.getString("testproduct_buffer");
HashMap<String, String> hmBuyCategories = new HashMap<String,String>();
hmBuyCategories.put("txt", "Categorie : " + name);
hmBuyCategories.put("pri", "Price : " + price);
hmBuyCategories.put("bes","Currency : " + path);
int imageId = getResources().getIdentifier("jollocks.logle:drawable/" + path, null, null);
hmBuyCategories.put("pic", Integer.toString(imageId) );
buyCategories.add(hmBuyCategories);
}
String responseStr = EntityUtils.toString(resEntity).trim();
Log.v(TAG, "Response: " + responseStr);
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
Toast.makeText(getApplicationContext(), "Errortest" + e.toString(),
Toast.LENGTH_SHORT).show();
}
String[] from = { "pic","txt","pri", "bes" };
int[] to = { R.id.buffer,R.id.name, R.id.price, R.id.beschreibung};
ListView listView = ( ListView ) findViewById(R.id.sampleListView);
SimpleAdapter simpleAdapter = new SimpleAdapter(this, buyCategories,
R.layout.list_item_product,
from, to);
listView.setAdapter(simpleAdapter);
}
您可以使用volley库。Android volley是一个网络库，它的引入使网络调用更容易、更快，而无需编写大量代码。默认情况下，所有的网络调用都是异步工作的，所以我们不必再担心使用asynctask。
http://developer.android.com/training/volley/simple.html首先，您应该将代码移动到单独的线程中以避免ANR。您可以使用AsyncTask，但要注意内存泄漏。否则，您可以使用建议的volley或OkHttp。它们是帮助您管理HTTP连接并在单独线程中处理请求的库。
例如，如果你想使用OkHttp:
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder().url(url).build();
client.newCall(request).enqueue(new Callback() {
@Override
public void onFailure(Request request, IOException e) {
// Notify error
}
@Override
public void onResponse(Response response) throws IOException {
// Here you parse the response
// when ready update the View
handler.post(new Runnable() {
@Override
public void run() {
// Here you update the listview
}
});
}
});
希望对你有帮助!!
首先，你应该知道在主UI上运行这段代码会给你错误，你试着在AsyncTask中实现它。
第二，"JSONObject jsonResponse = new JSONObject(jsonResult);"你在哪里声明"jsonResult"变量，根据你的代码，我看不到你在哪里声明。另外，你应该知道DefaultHttpClient现在已被弃用，最好使用UrlConnect进行http调用。最后我同意Patil的观点，你应该掌握一些android网络库，如Retrofit或Volley，因为你是一个初学者。