我有一个巨大的在线php动态文件集。它有链接，甚至一些无效的引号(与frontpage)
index2.php?page=xd
index2.php?page=xj asdfa
index2.php?page=xj%20aas
index2.php?page=xj#jumpword
index2.php?page=gj#jumpword with spaces that arenot%20
index2.php?page=afdsdj#jumpword%20with
index2.php?page=xj#jumpword with "quotes" iknow
$input_lines=preg_replace("/(index2.php?page'=.*)(#[a-zA-Z0-9_ ''"]*)('"'>)/U", "$0 --> $2", $input_lines);
我希望所有这些只是与# -部分，而不是有index2.php?页面= *部分。
整个晚上我都无法让这个工作。所以请帮忙。
在某些情况下，您可以使用parse_url从URL获取属性(例如:#后面的内容)，如下所示:
$urls = array(
'index2.php?page=xd',
'index2.php?page=xj asdfa',
'index2.php?page=xj%20aas',
'index2.php?page=xj#jumpword',
'index2.php?page=gj#jumpword with spaces that arenot%20',
'index2.php?page=afdsdj#jumpword%20with',
'index2.php?page=xj#jumpword with "quotes" iknow',
);
foreach($urls as $url){
echo 'For "' . $url . '": ';
$parsed = parse_url($url);
echo isset($parsed['fragment']) ? $parsed['fragment'] : 'DID NOT WORK';
echo '<br>';
}
For "index2.php?page=xd": DID NOT WORK
为"index2.php吗?page=xj asdfa": DID NOT WORK
For "index2.php?page=xj%20aas": DID NOT WORK
For "index2.php?page=xj#jumpword": jumpword
为"index2.php吗?Page =gj#jumpword with空格不为%20";
For "index2.php?page=afdsdj#jumpword%20with": jumpword%20with
为"index2.php吗?Page =xj#jumpword with "quotes"我知道用"引号"连词我深知