我需要生成带有条件的随机密码:
- 允许使用除">l1o0"以外的所有字符
- 长度为 8 到 12 个字符
我尝试过的代码:
function generateRandomPassword() {
//Initialize the random password
$password = '';
//Initialize a random desired length
$desired_length = rand(8, 12);
for($length = 0; $length < $desired_length; $length++) {
//Append a random ASCII character (including symbols)
$password .= chr(rand(32, 126));
}
return $password;
}
如何避免这4个字符=>">l1o0"?
原因:
- 这 4 个字符有时会让用户感到困惑。
谢谢!
请不要使用当前提供的任何其他答案来生成密码。无论如何,它们都不安全。
-
rand()
-> 否 -
mt_rand()
-> 绝对不是
我将从一篇标题为"如何在PHP中安全地生成随机字符串和整数"的博客文章中提取此解决方案。
/**
* Note: See https://paragonie.com/b/JvICXzh_jhLyt4y3 for an alternative implementation
*/
function random_string($length = 26, $alphabet = 'abcdefghijklmnopqrstuvwxyz234567')
{
if ($length < 1) {
throw new InvalidArgumentException('Length must be a positive integer');
}
$str = '';
$alphamax = strlen($alphabet) - 1;
if ($alphamax < 1) {
throw new InvalidArgumentException('Invalid alphabet');
}
for ($i = 0; $i < $length; ++$i) {
$str .= $alphabet[random_int(0, $alphamax)];
}
return $str;
}
用法:
// Every ASCII alphanumeric except "loIO01":
$alphabet = 'abcdefghijkmnpqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ23456789';
$string = random_string(12, $alphabet);
你可能没有random_int()
,除非你将来在 PHP 7 发布时阅读这篇文章。对于我们这些活在当下的人来说,使用random_compat。
试试这个:
function generateRandomPassword($length = 8) {
$characters = '23456789abcdefghjklmnpqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ';
$charactersLength = strlen($characters);
$randomPassword = '';
for ($i = 0; $i < $length; $i++) {
$randomPassword .= $characters[rand(0, $charactersLength - 1)];
}
return $randomPassword;
}
你不需要
更改你的代码。 只需使用str_replace替换那些单词的 您可以尝试此解决方案:)。刚刚编辑了您的代码
function generateRandomPassword($length = 8) {
$characters = '23456789abcdefghjklmnpqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ';
$charactersLength = strlen($characters);
$randomPassword = '';
for ($i = 0; $i < $length; $i++) {
$randomPassword .= $characters[rand(0, $charactersLength - 1)];
}
return str_replace(['l','1','o','0'], ['A','B','C','D'], $randomPassword);
}
$string = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
$req_pword_len = 20;
$char_count = 0;
$password='';
$chars=str_split($string);
while ( $char_count < $req_pword_len ) {
$char = mt_rand(0,61);
$password .= (string) $chars[$char];
$char_count++;
}
更改的值
- $string只是您想要允许的角色
- $req_pword_len 到所需的密码长度
试试这个:
function generateRandomPassword($length = 8) {
$randomPassword = '';
for ($i = 0; $i < $length; $i++) {
while (true) {
//remove 0,1,I,O,l,o
while(in_array(($number = rand(65, 122)), array(48, 49, 73, 79, 108, 111)));
if ($number <= 90 or $number >= 97) {
$randomPassword .= chr($number);
break ;
}
}
}
return $randomPassword;
}
echo generateRandomPassword();