我有以下DB:
...
`id` int(8) NOT NULL auto_increment,
`title` varchar(60) NOT NULL default '',
`date_firstcall` timestamp NOT NULL default CURRENT_TIMESTAMP,
`cid` int(8) NOT NULL default '1',
...
SELECT apv.title,apv.date_firstcall, COUNT( date_firstcall ) AS totalViews, DAYNAME(apv.date_firstcall) AS Tag FROM AnalysePageview apv GROUP BY TO_DAYS(date_firstcall), apv.title ORDER BY apv.date_firstcall DESC
我将得到这样一个表:
title date_firstcall totalViews Tag
name A 2014-08-25 10:19:49 2 Monday
name B 2014-08-25 07:04:36 2 Monday
name B 2014-08-24 16:03:36 3 Sunday
name C 2014-08-24 14:54:47 2 Sunday
name D 2014-08-24 10:25:35 1 Sunday
name A 2014-08-24 00:01:45 24 Sunday
name C 2014-08-23 11:06:19 3 Saturday
name A 2014-08-23 00:05:35 16 Saturday
name B 2014-08-22 10:05:53 4 Friday
name A 2014-08-22 00:11:28 25 Friday
name C 2014-08-21 19:28:54 1 Thursday
name A 2014-08-21 08:44:05 13 Thursday
name C 2014-08-20 22:42:49 1 Wednesday
name E 2014-08-20 03:04:03 1 Wednesday
name A 2014-08-20 00:25:01 23 Wednesday
name C 2014-08-19 16:27:03 2 Tuesday
name D 2014-08-19 16:22:42 2 Tuesday
name A 2014-08-19 15:43:57 10 Tuesday
name B 2014-08-19 09:36:52 1 Tuesday
name E 2014-08-18 20:31:06 1 Monday
name C 2014-08-18 18:51:15 19 Monday
name B 2014-08-18 17:52:21 4 Monday
name D 2014-08-18 14:55:52 3 Monday
我想要一个从今天开始的上周的表(今天是星期一;):
Monday Sunday Saturday Friday ...
name A 2 24 0
name B 2 3
，是否有可能得到不同语言的日名?
请在你将它标记为double之前:我看过其他pivot问题，没有人在处理可变日格式
关于你的语言问题:
您可以使用查询查看所选择的语言:选择@@lc_time_names;
之后你可以设置你自己的by:SET lc_time_names = 'YOUR_LC_TIME';
如果你想改变一周中每天的"顺序"，你可以编写一个程序来改变它，或者只是创建一个if/else语句来"改变"这些天的原始顺序。
我找到了一个解决方案:
首先，我在pivot-sql语句之外创建了一个帮助表。
$sql = "DROP VIEW IF EXISTS tmp";
$result = mysqli_query($link, $sql);
$sql = "CREATE VIEW tmp AS SELECT apv.title,apv.date_firstcall,
COUNT( date_firstcall ) AS totalViews,
DAYNAME(apv.date_firstcall) AS Tag FROM AnalysePageview apv
WHERE apv.date_firstcall > CURRENT_DATE - INTERVAL 6 DAY
GROUP BY TO_DAYS(date_firstcall),
apv.title ORDER BY apv.date_firstcall DESC";
$result = mysqli_query($link, $sql);
$sql = "SELECT title as Seite,
sum( if( Tag = 'Monday', totalViews, 0 ) ) AS Montag,
sum( if( Tag = 'Tuesday', totalViews, 0 ) ) AS Dienstag,
sum( if( Tag = 'Wednesday', totalViews, 0 ) ) AS Mittwoch,
sum( if( Tag = 'Thursday', totalViews, 0 ) ) AS Donnerstag,
sum( if( Tag = 'Friday', totalViews, 0 ) ) AS Freitag,
sum( if( Tag = 'Saturday', totalViews, 0 ) ) AS Samstag,
sum( if( Tag = 'Sunday', totalViews, 0 ) ) AS Sonntag
FROM tmp GROUP BY title";