如果一个条件从一个类函数到另一个类函数是真的,我正在尝试获取变量的值。
你能告诉我我该怎么做吗(我是PHP的新手。
法典:
class ErrorList{
static function getErrorsSince($delay, $criteria = NULL) {
global $appsFeXref, $table_error,$table_error_dis, $table_occurrence, $table_status, $table_fe_parameters, $debugMode;
if ($criteria->isValid()){
$var1 = '123';
}
}
Class Error{
function initFromDb($initDetails = false) {
global $appsFeXref, $table_error, $table_status, $table_fe_parameters, $table_error_dis;
$details = ($initDetails)? ", s.last_time, s.last_time_origin, s.last_time_machine, s.last_time_text, s.last_time_peak, ed.comment ":"";
$test = $var1;
echo "$test";
}
在这里你可以看到我需要从ErrorList
类到Error
类$var1
变量值。
提前谢谢。
问候特杰什·
<?php
class ErrorList{
static function getErrorsSince($delay, $criteria = NULL) {
global $appsFeXref, $table_error,$table_error_dis, $table_occurrence, $table_status, $table_fe_parameters, $debugMode;
if ($criteria->isValid()){
$var1 = '123';
return $var1;
}
}
}
class Error{
function initFromDb($initDetails = false) {
global $appsFeXref, $table_error, $table_status, $table_fe_parameters, $table_error_dis;
$details = ($initDetails)? ", s.last_time, s.last_time_origin, s.last_time_machine, s.last_time_text, s.last_time_peak, ed.comment ":"";
$call_class = new ErrorList();
$get_val = $call_class->getErrorsSince();
$test = $get_val;
echo $test;
}
}
?>