Codeigner当我提交form_multiselect（）的多个选项时，只有最后一个保存在数据库中。
在我看来：
<label>Trimestres :</label>
<div class="controls" >
<?php $options = array(
'trim1' => ' Premier trimestre (Janv,Fév,Mars)',
'trim2' => ' Deuxiéme trimestre (Avril,Mai,Juin)',
'trim3' => ' Troisiéme trimestre (Juill,Aout,Sept)',
'trim4' => ' Quatriéme trimestre (Oct,Nov,Déc)',
);
echo form_multiselect('trimestres', $options , $this->input->post('trimestres') ? $this->input->post('trimestres') : $participant_sport->trimestres, 'id="trim"'); ?>
</div>
</div>
在我的控制器中：
public function inscriresport ($id = NULL)
{
// Fetch a participant or set a new one
if ($id) {
$this->data['participant_sport'] = $this->participantsport_m->get($id);
count($this->data['participant_sport']) || $this->data['errors'][] = 'participant non trouvé';
}
else {
$this->data['participant_sport'] = $this->participantsport_m->get_new();
}
// Process the form
$this->participantsport_m->array_from_post(array('matricule', 'nom', 'prenom', 'beneficiaire', 'sexe', 'telephone', 'date_naissance', 'date_inscription_sport', 'trimestres' ,'sport_montant_paye', 'sport_debut_periode', 'sport_fin_periode'));
$this->participantsport_m->save($data, $id);
redirect('admin/agent/profile/3608');
}
// Load the view
$this->data['subview'] = 'admin/agent/inscriresport';
$this->load->view('admin/_layout_main', $this->data);
}
函数array_from_post（）在application''core''MY_Model.php上定义：
public function array_from_post($fields){
$data = array();
foreach ($fields as $field) {
$data[$field] = $this->input->post($field);
}
return $data;
}
在我的模型中：
public function get_new()
｛
$participant_sport = new stdClass();
$participant_sport->matricule = '';
$participant_sport->nom = '';
$participant_sport->prenom = '';
$participant_sport->beneficiaire = '';
$participant_sport->sexe = '';
$participant_sport->telephone = '';
$participant_sport->date_naissance = '';
$participant_sport->date_inscription_sport = '';
$participant_sport->trimestres = '';
$participant_sport->sport_montant_paye = '';
$participant_sport->sport_debut_periode = '';
$participant_sport->sport_fin_periode = '';
return $participant_sport;
}
有什么帮助吗？我想那一定是一个数组，但我不知道怎么做？
我认为我必须做这样的事情：
foreach($_POST["strategylist[]"] as $s) {
# do the insert here, but use $s instead of $_POST["strategylist[]"]
$result=mysql_query("INSERT INTO sslink (study_id, strategyname) " .
"VALUES ('$id','" . join(",",$s) . "')")
or die("Insert Error: ".mysql_error());
}
在一行中插入多个选择的选项，但我不知道如何在代码点火器中做到这一点
get（）函数：
public function get($id = NULL, $single = FALSE){
if ($id != NULL) {
$filter = $this->_primary_filter;
$id = $filter($id);
$this->db->where($this->_primary_key, $id);
$method = 'row';
}
elseif($single == TRUE) {
$method = 'row';
}
else {
$method = 'result';
}
if (!count($this->db->ar_orderby)) {
$this->db->order_by($this->_order_by);
}
return $this->db->get($this->_table_name)->$method();
}
如果选择名称（在HTML标记中）是trimestres，它将始终记住上次选择。使用trimestres[]作为名称获取具有所有选定值的数组`
<select name="trimestres[]" multiple …
顺便说一句：我不知道array_from_post()是如何工作的，但它必须将trimestres[]值更改为一个字符串才能将所有值保存在一列中。如果所有值都在一个字符串中，则很难搜索/添加/删除一个值。它是"SQL反模式"。您可以在数据库中为trimestres创建另一个表——一行中有一个值。
编辑：
它会将所有数组更改为字符串，其中元素由,连接。未经测试。
public function array_from_post($fields){
$data = array();
foreach ($fields as $field) {
// print_r($this->input->post($field));
if( is_array( $this->input->post($field) ) ) {
$data[$field] = join(",", $this->input->post($field));
} else {
$data[$field] = $this->input->post($field);
}
// print_r($data[$field]);
}
return $data;
}
编辑：
未经测试。
public function inscriresport ($id = NULL)
{
// Fetch a participant or set a new one
if ($id) {
$this->data['participant_sport'] = $this->participantsport_m->get($id);
count($this->data['participant_sport']) || $this->data['errors'][] = 'participant non trouvé';
// explode to array
// print_r($this->data['participant_sport']->trimestres); // test before explode
// $this->data['participant_sport']['trimestres'] = explode(",", $this->data['participant_sport']['trimestres']);
$this->data['participant_sport']->trimestres = explode(",", $this->data['participant_sport']->trimestres);
// print_r($this->data['participant_sport']->trimestres); // test after explode
} else {
$this->data['participant_sport'] = $this->participantsport_m->get_new();
}
// rest of code
}
有一种简单的方法可以解决我今天发现的这个问题。您必须在array_form_POST之后序列化$_POST['trimestres']数组。this数组将作为序列化字符串保存到数据库中。
public function inscriresport ($id = NULL)
{
// Fetch a participant or set a new one
if ($id) {
$this->data['participant_sport'] = $this->participantsport_m->get($id);
count($this->data['participant_sport']) || $this->data['errors'][] = 'participant non trouvé';
}
else {
$this->data['participant_sport'] = $this->participantsport_m->get_new();
}
// Process the form
$this->participantsport_m->array_from_post(array('matricule', 'nom', 'prenom', 'beneficiaire', 'sexe', 'telephone', 'date_naissance', 'date_inscription_sport', 'trimestres' ,'sport_montant_paye', 'sport_debut_periode', 'sport_fin_periode'));
$data['trimestres'] = serialize($_POST['trimestres']);
$this->participantsport_m->save($data, $id);
redirect('admin/agent/profile/3608');
}
// Load the view
$this->data['subview'] = 'admin/agent/inscriresport';
$this->load->view('admin/_layout_main', $this->data);
}
当您只需要从数据库返回此数据时，只需使用phpunserialize（）函数。希望这将有助于轻松做到这一点。。。。
-感谢