我试图创建一个导航,而使用smarty第一次。我想要显示所有的类别,除了我想要捕获并稍后使用的类别。
我让它工作,得到类别,并把它们放在列表中。但是,正在被捕获的一个类别没有显示在我希望它显示的地方。
我的类别Soccer //
subCat1 // those categories should be captured
subCat2 //
subCat3 //
Rugby
subCat1
subCat2
subCat3
Netball
subCat1
subCat2
subCat3
etc...
所以我的代码是这样的:
<div>
<!-- deal with category levels -->
{if empty($category_level)}
{assign var="category_level" value=1}
{else}
{math equation="x + 1" x=$category_level assign="category_level"}
{/if}
{assign var="captured" value="false"}
{foreach from=$categories item="category"}
{if (strstr($category.name, 'Soccer') == true)}
{assign var="captured" value="y"}
{assign var="capItem" value="soccerCats"} <!-- used it to see whether the condition was met and this code has been run -- this has been assigned corerctly -->
{capture name="soccerCats" assign="soco"} <!-- start capturing if above condition was met -->
{/if}
{if $category.level == $category_level && $category.is_visible == "Yes"}
<ul>
<li class="{$category.name|htmlspecialchars}Cat"><a href="{$category.category_url}">{$category.name|htmlspecialchars}</a><a class="mobileOnly"><i class="fa fa-angle-down fa-fw"></i></a>
{if !empty($category.children)}
<ul>
{assign var="categories" value=$category.children}
{if empty($category_level)}
{assign var="category_level" value=1}
{else}
{math equation="x + 1" x=$category_level assign="category_level"}
{/if}
{foreach from=$categories item="category"}
{if $category.level == $category_level && $category.is_visible == "Yes"}
<li><a href="{$category.category_url}">{$category.name|htmlspecialchars}</a></li>
{/if}
{/foreach}
{math equation="x - 1" x=$category_level assign="category_level"}
{assign var="category" value=0}
</ul>
{/if}
</li>
</ul>
{/if}
{if $captured == "y"}
{/capture} <!-- end the capture -->
{assign var="captured" value="n"}
{/if}
{/foreach}
{math equation="x - 1" x=$category_level assign="category_level"}
{assign var="category" value=0}
</div>
<!-- I tried to use both ways shown below to display the captured item -->
{$soco}
{$smarty.capture.soccerCats}
知道为什么会这样吗?
我不认为{capture}
可以在{if}
标签内工作,如果可以,我建议不要这样做,以获得更好的代码可读性。试试这样做:
<div>
<!-- deal with category levels -->
{if empty($category_level)}
{assign var="category_level" value=1}
{else}
{math equation="x + 1" x=$category_level assign="category_level"}
{/if}
{foreach from=$categories item="category"}
{capture name="code"}
<ul>
<li class="{$category.name|htmlspecialchars}Cat"><a href="{$category.category_url}">{$category.name|htmlspecialchars}</a><a class="mobileOnly"><i class="fa fa-angle-down fa-fw"></i></a>
{if !empty($category.children)}
<ul>
{assign var="categories" value=$category.children}
{if empty($category_level)}
{assign var="category_level" value=1}
{else}
{math equation="x + 1" x=$category_level assign="category_level"}
{/if}
{foreach from=$categories item="category"}
{if $category.level == $category_level && $category.is_visible == "Yes"}
<li><a href="{$category.category_url}">{$category.name|htmlspecialchars}</a></li>
{/if}
{/foreach}
{math equation="x - 1" x=$category_level assign="category_level"}
{assign var="category" value=0}
</ul>
{/if}
</li>
</ul>
{/capture}
{if (strstr($category.name, 'Soccer') != true)}
{$smarty.capture.code}
{else}
{$soccercats=$smarty.capture.code} {*Updated with @Borgtex's comment*}
{/if}
{/foreach}
</div>
{$soccercats}
这个想法是,你捕获一切,如果类别不是"足球",你显示捕获的数据;否则,您将它分配给另一个捕获,以便在循环之外最后使用它。代码假设存在一个单个足球类别,正如您在问题中最初所述。