编辑：

我花了很长时间，但我想到了以下内容：

function replaceLinks($replacements, $string){
    foreach($replacements as $key=>$val){
        $key=strtolower((string)$key);
        $newReplacements[$key]=array();
        $newReplacements[$key]['id']=$val;
        //strings to make sure the search isn't in front of
        $newReplacements[$key]['behinds']=array();
        //strings to make sure the search isn't behind
        $newReplacements[$key]['aheads']=array();
        //check for other searches this is a substring of
        foreach($replacements as $key2=>$val2){
            $key2=(string)$key2;
            /* 
            //debugging
            $b = ($key=='11 22'&&$key2=='11 22 33');
            if($b){
                l('strlen $key2: '.strlen($key2));
                l('strlen $key: '.strlen($key));
                l('strpos: '.(strpos($key2,$key)));
            }
            */
            //the second search is longer and the first is a substring of it
            if(strlen($key2)>strlen($key) && ($pos=strpos($key2,$key))!==false){
                //the first search isn't at the start of the second search ('the ford' and 'ford')
                if($pos!=0){
                    $newReplacements[$key]['behinds'][]=substr($key2,0,$pos);
                }
                //it's not at the end ('ford' and 'fords')
                if(($end=$pos+strlen($key))!=strlen($key2)){
                    $newReplacements[$key]['aheads'][]=substr($key2,$end);
                }
            }
        }
    }
    foreach($newReplacements as $key=>$item){
        //negative lookbehind for words or >
        $tmp="/(?<!['w>=])";
        //negative lookbehinds for the beginnings of other searches that this search is a subtring of
        foreach($item['behinds'] as $b){
            $tmp.="(?<!$b)";
        }
        //the actual search
        $tmp.="($key)";
        //negative lookaheads for ends of other searches that this is a substring of.
        foreach($item['aheads'] as $a){
            $tmp.="(?!$a)";
        }
        //case insensitive
        $tmp.='/ie';
        $replacementMatches[]=$tmp;
    }
    return preg_replace($replacementMatches,'"<a href='"".$newReplacements[strtolower("$1")]["id"]."'">$1</a>"' ,$string);
}

给它一个数组，就像你刚才说的那个：

$replaceWith = array('ford mustang'=>123,'ford'=>42,'honda'=>324);

和一个字符串：

$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";
echo replaceLinks($replaceWith,$string);

它优先考虑较大的字符串键，因此如果您有ford和ford mustang，它将用链接替换ford mustang。

不太实用，但可能有用。

$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";
$remove = array("/(?<!['w>])ford mustang(?!['w<])/",'/(?<![>'w])ford(?! mustang)(?![<'w])/',"/(?<![>'w])honda(?![<'w])/");
$replaceWith = array("<a href='fordmustangID'>ford mustang</a>","<a href='fordID'>ford</a>","<a href='hondaID'>honda</a>");
echo preg_replace($remove, $replaceWith,$string);

我使用了带有负lookahead和lookbehinds的正则表达式，以确保我们要替换的字符串部分不是字母数字序列的一部分（如12ford23或afford），也不是接触元素的开始或结束标记