我正在尝试在我的网站上检索一个特定的字符串。http://plpemag.byethost31.com/functions.php?action=printSpecificArticle&articleid=2通过android，并将其显示在我的文本视图中。但是当我运行程序时，文本视图仍然是空白的。这可能有什么问题？
GetMethodEx.java
package com.example.navigationdrawerexample;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URI;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
public class GetMethodEx {
public String getInternetData() throws Exception{
BufferedReader in = null;
String data = null;
try{
HttpClient client = new DefaultHttpClient();
URI website = new URI("http://plpemag.byethost31.com/functions.php?action=printSpecificArticle&articleid=2");
HttpGet request = new HttpGet();
request.setURI(website);
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String l = "";
String nl = System.getProperty("line.separator");
while ((l = in.readLine()) !=null){
sb.append(l+nl);
}
in.close();
data = sb.toString();
return data;
}finally{
if (in != null){
try{
in.close();
return data;
} catch (Exception e){
e.printStackTrace();
}
}
}
}
}
CollegeBulletinListFragment.java
package com.example.navigationdrawerexample;
import android.app.Fragment;
import android.os.Bundle;
import android.app.Fragment;
import android.app.FragmentManager;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.TextView;
public class CollegeBulletinListFragment extends Fragment{
public CollegeBulletinListFragment(){
}
TextView kem;
TextView tester;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragment_collegebulletinlist, container, false);
kem = (TextView) rootView.findViewById(R.id.angkembular);
tester = (TextView) rootView.findViewById(R.id.tester);
Bundle bun = getArguments();
setTextAndColorsToHead(bun.getString("passingWord"));
GetMethodEx gm = new GetMethodEx();
String returned;
try {
returned = gm.getInternetData();
tester.setText(returned);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return rootView;
}
public void setTextAndColorsToHead(String arg){
if (arg.equals("GN")){
kem.setText("General News");
} else if (arg.equals("CCS")){
kem.setText("College of Computer Studies");
} else if (arg.equals("COE")){
kem.setText("College of Engineering");
} else if (arg.equals("COED")){
kem.setText("College of Education");
} else if (arg.equals("CON")){
kem.setText("College of Nursing");
} else if (arg.equals("CBA")){
kem.setText("College of Business and Accountancy");
} else if (arg.equals("CAS")){
kem.setText("College of Arts and Sciences");
} else if (arg.equals("CIHM")){
kem.setText("College of International and Hospitality Management");
}
}
}
链接：http://plpemag.byethost31.com/functions.php?action=printSpecificArticle&articleid=2给出了从数据库中提取的数据的json格式。现在我们需要使用json格式中的变量名来解析这个json格式。例如，如果我们需要内容变量，我们可以使用获得它
@Override
protected void onPostExecute(JSONArray jsonArray){
setTextView(jsonArray);
}
onPostExecute方法是Asynctask的一部分。如果你想要，请告诉我。
setTextView(JSONArray jsonArray){
for(int i = 0; i<jsonArray.length();i++){
////////////////here you are iterating through all the arrays in json file.
try{
json = jsonArray.getJSONObject(i);
cont = json.getString("content");/////this brings the text in content variable to variable cont.
}catch(JSONException e){
e.printStackTrace();
}
}
现在使用cont变量并将其分配给文本视图。希望这能有所帮助。
我遇到了同样的问题，因为我没有使用异步任务。
new GetTextTask().execute(new ApiConnector());
/////////////////call this when you want to parse the json page.
这是异步任务
private class GetTextTask extends AsyncTask<ApiConnector,Long,JSONArray>{
@Override
protected JSONArray doInBackground(ApiConnector... params) {
return params[0].GetText();
}
@Override
protected void onPostExecute(JSONArray jsonArray){
setTextView(jsonArray);
}
}
您还需要Apiconnector类
public class ApiConnector {
public JSONArray GetText(){
String url = "your url for php";
HttpEntity httpEntity = null;
try{
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
httpEntity = httpResponse.getEntity();
}catch (ClientProtocolException e){
e.printStackTrace();
}catch (IOException e){
e.printStackTrace();
}
JSONArray jsonArray = null;
if(httpEntity != null){
try{
String entityResponse = EntityUtils.toString(httpEntity);
Log.e("Entity Response: ", entityResponse);
jsonArray = new JSONArray(entityResponse);
}catch(JSONException e){
e.printStackTrace();
}catch (IOException e){
e.printStackTrace();
}
}
return jsonArray;
}
希望这能有所帮助。