使用true选项,效果良好。
抱歉,谢谢大家。
=========================================
我用以下代码将php数组编码为json
$rows = array();
if ($result = $mysqli->query($query)) {
while ($row = $result->fetch_assoc()) {
$rows[] = $row;
}
echo json_encode($rows);
/* free result set */
$result->free();
}
使用结束解码
$array = json_decode($server_output)
$server_output类似于这个
[{"userid":"96679","userinfor":"xxxxxxxxx","userlocation":"CA"}]
[{"userid":"153795","userinfor":"xxxxxxxxx","userlocation":"CA"}]
[{"userid":"131878","userinfor":"xxxxxxxxx","userlocation":"CA"}]
但是,$array为NULL:(
特别感谢
这是无效的json:
[{"userid":"96679","userinfor":"xxxxxxxxx","userlocation":"CA"}]
[{"userid":"153795","userinfor":"xxxxxxxxx","userlocation":"CA"}]
[{"userid":"131878","userinfor":"xxxxxxxxx","userlocation":"CA"}]
同时,此部分有效:
[{"userid":"96679","userinfor":"xxxxxxxxx","userlocation":"CA"}]
或者它们中的任何一个单独
$json = '[{"userid":"96679","userinfor":"xxxxxxxxx","userlocation":"CA"}]';
print_r(json_decode($json, true));
输出:
Array
(
[0] => Array
(
[userid] => 96679
[userinfor] => xxxxxxxxx
[userlocation] => CA
)
)
所有数据的有效格式如下:
[
{
"userid": "96679",
"userinfor": "xxxxxxxxx",
"userlocation": "CA"
},
{
"userid": "153795",
"userinfor": "xxxxxxxxx",
"userlocation": "CA"
},
{
"userid": "131878",
"userinfor": "xxxxxxxxx",
"userlocation": "CA"
}
]