当数据库更新时,我正试图从中获取返回值。我使用AJAX通过Wordpress插件的文件夹将数据发送到functions.php中的一个函数。我试着对成功和失败函数发出警报,它总是调用失败函数。我如何知道AJAX响应是否成功,以便在成功时可以做一些额外的代码。
脚本
function removeUser( department , user ){
var value = { user_id: user , dep_name: department.id };
$('#'+department.id+ user +"_div").hide();
$.ajax({
type: "POST",
data: value
});
}
functions.php
function removeUser(){
if(isset($_POST['user_id'])){
//echo $_POST['user_id'];
//echo $_POST['dep_name'];
$user_meta = get_user_meta($_POST['user_id'], 'wpwf_quotation_position');
$user_department = json_decode ($user_meta[0]);
//print_r ($user_department);
//echo (json_encode($user_department));
foreach ($user_department as $key => $value){
if ($value == strtolower($_POST['dep_name'])){
//print_r ($user_department);
unset($user_department[$key]);
$user_department = array_values($user_department);
//print_r ($user_department);
//echo (json_encode($user_department));
//print_r (json_encode($user_department));
update_user_meta( $_POST['user_id'], 'wpwf_quotation_position', json_encode($user_department));
break;
}
//echo $key." : ". $value ." - " . strtolower($_POST['dep_name'])."<br>";
}
//echo 'ssss';
wp_send_json($_POST);
}
}
add_action('init', 'removeUser');
上面的代码运行得很好,但我实际上想做的如下,但没有调用success函数。我在这里错过了什么或者做错了什么?
function removeUser( department , user ){
var value = { user_id: user , dep_name: department.id };
$.ajax({
type: "POST",
data: value,
success:function() {
$('#'+department.id+ user +"_div").hide();
}
});
}
您应该使用浏览器控制台来调试这种事情。目前,我想说你得到了"undefined is not a function"的错误,这意味着它无法识别$,请使用安全模式jQuery(jQuery.ajax)。
此外,您还丢失了ajax调用中的url和操作。
function removeUser( department , user ){
var value = { action: 'removeUser'/*assuming this is your ajax action */, user_id: user , dep_name: department.id };
jQuery.ajax({
type: "POST",
url: "/wp-admin/admin-ajax.php",
data: value,
success:function(output) {
console.log(output); // have a look at the console to find your values prob something like output.user_id
jQuery('#'+department.id+ user +"_div").hide();
}
});
}
此外,我看不出您还将php函数连接到了wp_ajax。我想你已经这么做了?