根据不同表格中的日期显示数据


Show data according to date in different tables

我做了一个查询,在其中我显示了loggedin电子邮件id的珍贵购买数据。我已经成功地完成了这项工作。现在我想根据日期显示数据。这里显示了每一行的日期。有什么建议吗!!

代码

<h3>My Orders</h3>
<table border="1">
<?php
 $query="select orders.date,order_detail.quantity,order_detail.price,order_detail.color,order_detail.size,customers.name,products.product_name,products.product_image from order_detail JOIN orders on orders.serial=order_detail.orderid Join customers on customers.serial=orders.customerid Join products on products.productid=order_detail.productid where customers.email='$email'";
    $sql=mysqli_query($con,$query);
     while($row=mysqli_fetch_array($sql))
                {
                  ?>
      <tr>
      <td><?php echo $row['date'] ?></td>
      <td><image width="80px" height="90px" src="images/images/<?php echo $row['product_image'] ?>"/></td>
       <td><?php echo $row['product_name']. "*". $row['quantity']?></td>
       <td><?php echo $row['color'] ?></td>
       <td><?php echo $row['price'] ?></td>
       <td><?php echo $row['size'] ?></td>
               </tr>
                <?php
                }
                ?>
        </table> 

您尝试过根据日期对它们进行排序吗?这可以通过添加"ORDER BY column ASC"来增加值或添加"ORDER BY column DESC"来减少值来轻松完成!

$query="SELECT orders.date, order_detail.quantity, order_detail.price, 
    order_detail.color, order_detail.size, 
    customers.name, 
    products.product_name, 
    products.product_image 
    FROM order_detail 
    JOIN orders ON orders.serial=order_detail.orderid 
    JOIN customers ON customers.serial=orders.customerid 
    JOIN products ON products.productid=order_detail.productid 
    WHERE customers.email='$email'
    ORDER BY orders.date";

查看手册

如果您想将相同的日期分组在一起,请尝试group BY命令(如果orders.date的类型为date/DATETIME/TIMESTAMP,则此示例有效):

$query="SELECT orders.date, order_detail.quantity, order_detail.price, 
    order_detail.color, order_detail.size, 
    customers.name, 
    products.product_name, 
    products.product_image 
    FROM order_detail 
    JOIN orders ON orders.serial=order_detail.orderid 
    JOIN customers ON customers.serial=orders.customerid 
    JOIN products ON products.productid=order_detail.productid 
    WHERE customers.email='$email'
    GROUP BY DATE( orders.date )
    ORDER BY orders.date";

如果您使用PHP时间戳或INT,则需要像这样转换日期:GROUP BY DATE( FROM_UNIXTIME( orders.date ) )

DATE(col)将日期/日期时间/时间戳转换为一天。GROUP BY将所有具有相同DATE的行放在一行中。现在,您可能还想将显示的数据更改为SUM(order_detail.price),以获取当天的总价,依此类推。