当我尝试使用SQLite3 在PHP中创建忘记密码页面时，我收到了以下错误
Fatal error: Non-static method SQLite3::query() cannot be called statically in C:'xampp'htdocs's'sqlite'forgot.php on line 16
我正在尝试使用SQLite3在PHP中创建登录系统。我在整个登录过程中都做了正确的操作，但忘记密码让我头发花白：/这是我的忘记密码的PHP代码。哪个是Forget.php
<?php
class MyDB extends SQLite3
{
function __construct()
{
$this->open('test.db');
}
}
$db = new MyDB();
if(!$db)
{
echo $db->lastErrorMsg();
} else{ }
$query = SQLite3::query($db, 'SELECT email, password FROM user LIMIT 25');
$result = sqlite_fetch_all($query, SQLITE_ASSOC);
foreach ($result as $entry) {
echo 'Email: ' . $entry['email'] . ' Password: ' . $entry['password0'];
}
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Forgot Password</title>
</head>
<body>
<form action="" method="post">
<h1> Forgot password!</h1>
<label> Enter Your Email ID : </label>
<input id="email" type="email" name="email" required=" " />
<input id="button" type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
您应该知道创建$db对象的原因。正确地使用它，而不是静态地调用SQLite3::query（这不是一个静态函数）。
$query = $db->query('SELECT email, password FROM user LIMIT 25');
请参阅此处的示例以在SQLite3中运行查询http://php.net/manual/en/sqlite3.query.php