如果数组中已经存在，PHP会将计数器添加到名称中 - PHP add counter to name if already exists in array

PHP add counter to name if already exists in array

我有下面的多维数组，我需要对它进行迭代，只要有重复的名称，就会在名称中添加一个计数器。

[1] => Array
    (
        [0] => Array
            (
                [clientName] => John Smith
                [clientType] => 0
                [clientDOB] => 1980-10-14
            )
     )
[2] => Array
    (
        [0] => Array
            (
                [clientName] => John Smith
                [clientType] => 0
                [clientDOB] => 1970-01-01
            )
        [1] => Array
            (
                [clientName] => Jeremy White
                [clientType] => 2
                [clientDOB] => 2015-08-19
            )
    )

我使用的代码是：

$finalNames = array_map(function ($item) use (&$namesCount) {
    if (!isset($namesCount[$item['clientName']])) {
        $namesCount[$item['clientName']] = 0;
    }
    $namesCount[$item['clientName']]++;
    $item['clientName'] = $item['clientName'] . ' ' . $namesCount[$item['clientName']];
    return $item;
}, $arrayOfTravellers);
array_map(function($item, $key) use ($namesCount, &$finalNames) {
    $finalNames[$key]['clientName'] = $namesCount[$item['clientName']] == 1
        ? str_replace(' 1', '', $finalNames[$key]['clientName'])
        : $finalNames[$key]['clientName'];
}, $arrayOfNames, array_keys($arrayOfTravellers));

它返回了一堆错误，例如：注意：未定义的索引：第330行上/Applications/MAMP/htdocs/europatours/functions/reportsFunctions.php中的clientName

我的假设是，该代码不适合多维数组。有人能帮忙吗？我只需要在有重复名称的地方保留数组的完整结构，添加了一个计数器，如John Smith 1、John Smith 2，而Jeremy White仍然没有计数器。

$arrayOfNames = array(
    array('clientName' => 'John'),
    array('clientName' => 'John'),
    array('clientName' => 'Mary'),
    array('clientName' => 'Mary'),
    array('clientName' => 'Mary'),
    array('clientName' => 'Tony'),
    array('clientName' => 'Alex')
);
$namesCount = array();
$finalNames = array_map(function ($item) use (&$namesCount) {
    if (!isset($namesCount[$item['clientName']])) {
        $namesCount[$item['clientName']] = 0;
    }
    $namesCount[$item['clientName']]++;
    $item['clientName'] = $item['clientName'] . ' ' . $namesCount[$item['clientName']];
    return $item;
}, $arrayOfNames);
array_map(function($item, $key) use ($namesCount, &$finalNames) {
    $finalNames[$key]['clientName'] = $namesCount[$item['clientName']] == 1
        ? str_replace(' 1', '', $finalNames[$key]['clientName'])
        : $finalNames[$key]['clientName'];
}, $arrayOfNames, array_keys($arrayOfNames));
echo '<pre>';
    var_dump($finalNames);
echo '</pre>';

输出为：

array(7) {
  [0]=>
  array(1) {
    ["clientName"]=>
    string(6) "John 1"
  }
  [1]=>
  array(1) {
    ["clientName"]=>
    string(6) "John 2"
  }
  [2]=>
  array(1) {
    ["clientName"]=>
    string(6) "Mary 1"
  }
  [3]=>
  array(1) {
    ["clientName"]=>
    string(6) "Mary 2"
  }
  [4]=>
  array(1) {
    ["clientName"]=>
    string(6) "Mary 3"
  }
  [5]=>
  array(1) {
    ["clientName"]=>
    string(4) "Tony"
  }
  [6]=>
  array(1) {
    ["clientName"]=>
    string(4) "Alex"
  }
}

添加新值时，array_column和in_array的组合如何？

$records = array(); // your data
$name = 'John';
$i = 0;
do
{
    $newName = $name . ( ($i == 0)? '' : ' '.$i );
    $i++;
}
while (in_array($newName, array_column($records, 'clientName')));
$records[] = array('clientName' => $newName);

由于性能问题，您可能希望在循环之前只调用array_columns一次，并将结果存储在变量中。